anonymous
  • anonymous
Consider the following algorithm. x ← 1 for i is in {1, 2, 3, 4} do for j is in {1, 2, 3} do x ← x + x for k is in {1, 2, 3, 4, 5, 6} do x ← x + 1 x ← x + 5 Count the number of + operations done by this algorithm.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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ChillOut
  • ChillOut
Each outside loop will run the insider loop for every iteration. the "k" loop is inside the "j" loop, which in turn is inside the "i" loop. As it turns out, for every iteration of "j", we will have 1 + (6*2) = 13 operations. As we have 3 "j" iterations, this gives 39 "+" operations for each "i" iteration. So, for 4 "i" iterations, we have 4*39 = 156 "+" operations.
anonymous
  • anonymous
got it!! the answer is 60
ChillOut
  • ChillOut
How's it? Please give your solution.

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anonymous
  • anonymous
value of i = 4 for j = 3 for k = 6 x 2 4(3 + (6x2)) =60
anonymous
  • anonymous
i don't know if it makes sense. but I got it right!
ChillOut
  • ChillOut
Nope. I just tested it. Check it at http://ideone.com/GsQ3pj You should be able to understand. The program output is Success time: 0 memory: 3096 signal:0 156
ChillOut
  • ChillOut
Do you understand any programming languages?

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