1. anonymous

$\frac{ \sin ^{2} \theta }{ 1-\cos \theta }$

2. anonymous

3. anonymous

Write sin² Θ as 1 - cos² Θ then factor

4. anonymous

I'm not sure how to

5. anonymous

1 - cos² Θ is a difference of squares. Factoring it follows the pattern a² - b² = (a + b)(a - b) So a = 1 and b = cos Θ

6. anonymous

alright

7. anonymous

$1-1 = (1+\cos \theta)(1-\cos \theta)$

8. anonymous

1 - cos² Θ = (1 + cos Θ)(1 - cos Θ)

9. anonymous

ohhhhh ok I see now

10. anonymous

ya I messed up on the b^2 oops...

11. anonymous

so now what?

12. anonymous

that's the numerator. Cancel what you can with the denominator and see what's left

13. anonymous

oohhh is the answer $1+\cos \theta$

14. anonymous

yes

15. anonymous

so A?

16. anonymous

yes

17. anonymous

thank you