A partial sum of an arithmetic sequence is given. Find the sum. 10 over sigma k=0 under sigma. (3+0.25k) beside sigma

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A partial sum of an arithmetic sequence is given. Find the sum. 10 over sigma k=0 under sigma. (3+0.25k) beside sigma

Mathematics
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\[\Sigma (3+0.25k)\] with 10 on top and k=0 under the sigma
@freckles have time? :)

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would the first step be to solve for k? how do I do that? o.o
|dw:1434069542255:dw|
Start by plugging in 0 for k to solve for a0, then plug in 10 to find a10
oo not sn=(n/2)(a1+an) ?
no. Generally use a1 for the sum of the first n terms, but they started this one at 0
ah yes I see. ok.
so plug in 0 for k in 3+0.25k ? then a0 would be = 3
yes
Where do I plug the 10 in?
into the same formula
for k? = 5.5
yes
and that is what a_10 equals?
right
and n = 11
how'd you find that? o.o
10-0+1
..hah ok. so then the whole thing equals 46.75
basically there are 11 numbers from 0 to 10 inclusive
that's right
ah gotcha. That makes more sense.
yay!! thanks :)
you're welcome
n represents how many numbers there are in total then.
yes it does
okies. :)

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