(3x^2/4y^2)^-2 SIMPLIFY Help?

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(3x^2/4y^2)^-2 SIMPLIFY Help?

Mathematics
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|dw:1434068972553:dw|
|dw:1434069000316:dw|
after doing the flip, we will have |dw:1434069045031:dw|

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with me so far?
yep
now we square both top and bottom |dw:1434069090790:dw|
Since \[\Large \left(\frac{A}{B}\right)^2 = \frac{A^2}{B^2}\]
do you see how to finish up?
no, im still confused. do you jus multiply the eponents together or add?
you can think of \[\Large (4y^2)^2\] as \[\Large (4y^2)*(4y^2)\]
16y^4?
over 9x^4 right
lulubj, let the original asker answer the question I'm asking
i need it too
ohh i get what your doing though.
dont know if thats right though
it's correct
|dw:1434069298881:dw|
what if it was 4y^3 is it the same proccess?
yes same idea but the y exponent in the answer will be different
so it would be 4y^9?
16y^9 ?
|dw:1434069408797:dw|
the exponents 3 and 2 multiply to get 6
or you can think of it as y^3*y^3 = y^(3+3) = y^6
oh okay thanks! i get it :)
you're welcome

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