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Leahc246

  • one year ago

Can't seem to remember how to begin this one! The book asks me to simplify: √(5) ÷ 3 - √(2) Thank you so much!

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  1. Blondisaurus
    • one year ago
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    Are there answer choices?

  2. Leahc246
    • one year ago
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    There are!: (a) √(10) ÷ 3 √(2) - 2 (b) √(5) ÷ 3 √(5) - 10 (c) 3 √(5) - 10 ÷ 7 (d) 3 √(5) + √(10) ÷ 7

  3. Leahc246
    • one year ago
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    @Blondisaurus

  4. anonymous
    • one year ago
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    |dw:1434073784909:dw|

  5. Leahc246
    • one year ago
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    The second one!

  6. anonymous
    • one year ago
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    ok so you need to multiply the numerator and denominator by the conjugate of 3-√2. Any idea as to what that is?

  7. Leahc246
    • one year ago
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    Would that be |dw:1434074159518:dw|

  8. anonymous
    • one year ago
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    yes

  9. Leahc246
    • one year ago
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    Okay perfect

  10. anonymous
    • one year ago
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    |dw:1434074241396:dw|

  11. Leahc246
    • one year ago
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    Okay, so from what I'm seeing, 7 as the denominator wouldn't make much sense so c and d are out correct?

  12. anonymous
    • one year ago
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    not necessarily. Did you FOIL the denominator?

  13. Leahc246
    • one year ago
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    |dw:1434074631755:dw|

  14. Leahc246
    • one year ago
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    Lost it at the sqrt of 2 x sqrt of 2 for some reason!

  15. Leahc246
    • one year ago
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    The \[3\sqrt{2}\] should cancel out

  16. Leahc246
    • one year ago
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    due to the positive and negative

  17. anonymous
    • one year ago
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    |dw:1434074875366:dw|

  18. anonymous
    • one year ago
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    yes they do cancel out, and that should be 2, sorry

  19. anonymous
    • one year ago
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    |dw:1434074954769:dw|

  20. anonymous
    • one year ago
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    So for the denominator you're left with 9 - 2 = 7

  21. anonymous
    • one year ago
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    |dw:1434075009742:dw|

  22. Leahc246
    • one year ago
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    Oh wow! Math strikes again lol this is what I get for staying up cramming! Thank you for that!

  23. anonymous
    • one year ago
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    you're welcome

  24. Leahc246
    • one year ago
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    So the answer is d!

  25. anonymous
    • one year ago
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    yep!

  26. Leahc246
    • one year ago
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    Thank you so much for all of your help! SO very grateful right now!

  27. anonymous
    • one year ago
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    no problem. you're welcome

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