## Leahc246 one year ago Can't seem to remember how to begin this one! The book asks me to simplify: √(5) ÷ 3 - √(2) Thank you so much!

1. anonymous

2. Leahc246

There are!: (a) √(10) ÷ 3 √(2) - 2 (b) √(5) ÷ 3 √(5) - 10 (c) 3 √(5) - 10 ÷ 7 (d) 3 √(5) + √(10) ÷ 7

3. Leahc246

@Blondisaurus

4. anonymous

|dw:1434073784909:dw|

5. Leahc246

The second one!

6. anonymous

ok so you need to multiply the numerator and denominator by the conjugate of 3-√2. Any idea as to what that is?

7. Leahc246

Would that be |dw:1434074159518:dw|

8. anonymous

yes

9. Leahc246

Okay perfect

10. anonymous

|dw:1434074241396:dw|

11. Leahc246

Okay, so from what I'm seeing, 7 as the denominator wouldn't make much sense so c and d are out correct?

12. anonymous

not necessarily. Did you FOIL the denominator?

13. Leahc246

|dw:1434074631755:dw|

14. Leahc246

Lost it at the sqrt of 2 x sqrt of 2 for some reason!

15. Leahc246

The $3\sqrt{2}$ should cancel out

16. Leahc246

due to the positive and negative

17. anonymous

|dw:1434074875366:dw|

18. anonymous

yes they do cancel out, and that should be 2, sorry

19. anonymous

|dw:1434074954769:dw|

20. anonymous

So for the denominator you're left with 9 - 2 = 7

21. anonymous

|dw:1434075009742:dw|

22. Leahc246

Oh wow! Math strikes again lol this is what I get for staying up cramming! Thank you for that!

23. anonymous

you're welcome

24. Leahc246

25. anonymous

yep!

26. Leahc246

Thank you so much for all of your help! SO very grateful right now!

27. anonymous

no problem. you're welcome