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anonymous

  • one year ago

:)

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  1. UsukiDoll
    • one year ago
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    uhhhhhhhhh we can just plug in those values and solve?!!!

  2. anonymous
    • one year ago
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    YA I KNOW BUT EVERY TIME I MESS UP -_- AND I NEED HELP PLEASE!

  3. UsukiDoll
    • one year ago
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    \[2r^2+3s^3-r^2+4t^2-r^2\] \[-3a^2-b^3+3c^2-2b^3\]

  4. funnyguy2
    • one year ago
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    19 http://www.mathpapa.com/algebra-calculator.html

  5. UsukiDoll
    • one year ago
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    well ok.. we can combine like terms first to make it easier \[2r^2-r^2-r^2+3s^3+4t^2\] \[2r^2-2r^2+3s^3+4t^2\] \[3s^3+4t^2\] s=-3 t=5 \[3(-3)^3+4(5)^2\] \[3(-27)+4(25)\] \[-81+100=19\]

  6. UsukiDoll
    • one year ago
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    yup checks out on the first one I got 19 too, but at least I showed work :P

  7. anonymous
    • one year ago
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    The second question too i am confused on can you help with that too?

  8. anonymous
    • one year ago
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    Find −3a2 − b3 + 3c2 − 2b3 if a = 2, b = −1, and c = 3.

  9. UsukiDoll
    • one year ago
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    \[-3a^2-3b^3+3c^2\] a=2, b=-1, c = 3 \[-3(2)^2-3(-1)^3+3(3)^2\] \[-3(4)-3(-1)+3(9)\] \[-12+3+27 =18\]

  10. anonymous
    • one year ago
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    Thank you!

  11. funnyguy2
    • one year ago
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    Thank who?

  12. funnyguy2
    • one year ago
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    I would thank the creator of the algebra calculator.

  13. UsukiDoll
    • one year ago
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    ^which you shouldn't depend on.. because that's not really learning how to solve these problems.

  14. funnyguy2
    • one year ago
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    It shows you the steps!

  15. UsukiDoll
    • one year ago
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    True, but if OP has a closed book closed note test... then what? The only way to solve it is the manual way.

  16. UsukiDoll
    • one year ago
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    these sites that automatically solve the problem for you are only supposed to be used to check your answer... it shouldn't be a replacement to do the math the pencil and paper way.

  17. skullpatrol
    • one year ago
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    @cutiiepie7272 you must learn to replace each variable with a given value and simplify the resulting numerical expression.

  18. skullpatrol
    • one year ago
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    Any questions?

  19. skullpatrol
    • one year ago
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    This is called the substitution principle: An expression maybe replaced by another expression that has the same value.

  20. skullpatrol
    • one year ago
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    4 + 2 can be replaced by 6 because they have the same value 4 + 2 = 6. Similarly, if x = 6, then x can be replaced by 6 because they have the same value 6 = 6.

  21. skullpatrol
    • one year ago
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    Also, please use the "^" symbol for exponentiation :-)

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