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I'm finally almost done! I'm about ready to pass out...
I think you meant to write \[\Large (x-3)^5\] ??
I didn't write it, that's the problem, but ya that's what it is
ah I see
what I'm going to do is write out 6 rows of (x) and (-3) put together, but with a bit of space between them I'm doing 6 because the degree is 5, so there are 5+1 = 6 terms total |dw:1434075073618:dw|
the exponent for the x in row 1 will be 5, we start with the degree |dw:1434075149089:dw|
the exponent over -3 will be 0 we want the exponents for x and -3 to always add to 5 |dw:1434075177797:dw|
the x exponents will count down to 0 the -3 exponents will count up to 5 |dw:1434075199450:dw|
notice how each pair of exponents add back up to 5 eg: 3+2 = 5 |dw:1434075236860:dw|
the last thing needed are the binomial coefficients
we get those from pascals triangle or from the combination formula n C r
http://mathforum.org/workshops/usi/pascal/images/pascal.hex2.gif what are the numbers in the row that has "1, 5, ..."
1, 5, 10, 10, 5, 1
arrange those numbers vertically like so |dw:1434075368092:dw|
the next step is to simplify each row in the drawing to get the 6 terms then you add up the 6 terms to get the overall polynomial
I'll be right back
I have to finish this really soon... we're so close to being done!
I have to be done, its my last problem I'll get a little credit I'm turning it in how it is. thank you SO MUCH for all your help @jim_thompson5910 !
I'm back. Sorry about that but I'm glad it's making sense now