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anonymous
 one year ago
A bag contains 10 dimes and 4 quarters. You are going to select three coins at random, one at a time, without replacement. Find the probability of drawing a dime, then a quarter, then another quarter.
3/14
20/273
5/91
15/343
anonymous
 one year ago
A bag contains 10 dimes and 4 quarters. You are going to select three coins at random, one at a time, without replacement. Find the probability of drawing a dime, then a quarter, then another quarter. 3/14 20/273 5/91 15/343

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ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0How many coins are there total and how many dimes? Chance of getting a dime on the first then = #dimes/total number of coins Get this first

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Total 14, total dimes 10 so 10/14?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0Yes. Now, we need a dime first AND quarter second AND lastly a quarter, since these are independent, we will be multiplying. After we get our dime, how many coins are left and how many quarters are available? This will give us #quarters/total , this is the next term

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0You should have 4 quarters and 13 coins available, since we took one out on the 1st draw: $$ \cfrac{10}{14}\times\cfrac{4}{13}\times ? $$ What's the last term?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0Multiply and you get  http://www.wolframalpha.com/input/?i=%2810*4*9%29%2F%2814*13*12%29 Which is close to one of your options  maybe you left out a digit?

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434077226838:dw

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0These are all dependent variables. Thus you have the denominators decreasing every time you take it out ("without replacement").

calculusxy
 one year ago
Best ResponseYou've already chosen the best response.0@NANABE You're welcome :)
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