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anonymous
 one year ago
g(x)=3(1t)^24(1t)+14
g(1t)=?
anonymous
 one year ago
g(x)=3(1t)^24(1t)+14 g(1t)=?

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0is g(x) like below: g(x) = 3x^24x+14

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0if yes, the replacing x with 1t, we get: \[\large g\left( {1  t} \right) = 3{\left( {1  t} \right)^2}  4\left( {1  t} \right) + 14\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0please simplify the above expression

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm having trouble foiling, I think and then simplifying. I got to \[36t+3t ^{2}4+4t+14\]

freckles
 one year ago
Best ResponseYou've already chosen the best response.0I'm confused about the question g(x)=3(1t)^24(1t)+14 means g(x) is constant unless t is an expression of x

freckles
 one year ago
Best ResponseYou've already chosen the best response.0if g(x)=a where a is constant then g(1t)=a also
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