## anonymous one year ago g(x)=3(1-t)^2-4(1-t)+14 g(1-t)=?

1. Michele_Laino

is g(x) like below: g(x) = 3x^2-4x+14

2. Michele_Laino

if yes, the replacing x with 1-t, we get: $\large g\left( {1 - t} \right) = 3{\left( {1 - t} \right)^2} - 4\left( {1 - t} \right) + 14$

3. Michele_Laino

then*

4. Michele_Laino

please simplify the above expression

5. anonymous

I'm having trouble foiling, I think and then simplifying. I got to $3-6t+3t ^{2}-4+4t+14$

6. freckles

I'm confused about the question g(x)=3(1-t)^2-4(1-t)+14 means g(x) is constant unless t is an expression of x

7. freckles

if g(x)=a where a is constant then g(1-t)=a also