anonymous
  • anonymous
g(x)=3(1-t)^2-4(1-t)+14 g(1-t)=?
Mathematics
jamiebookeater
  • jamiebookeater
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Michele_Laino
  • Michele_Laino
is g(x) like below: g(x) = 3x^2-4x+14
Michele_Laino
  • Michele_Laino
if yes, the replacing x with 1-t, we get: \[\large g\left( {1 - t} \right) = 3{\left( {1 - t} \right)^2} - 4\left( {1 - t} \right) + 14\]
Michele_Laino
  • Michele_Laino
then*

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Michele_Laino
  • Michele_Laino
please simplify the above expression
anonymous
  • anonymous
I'm having trouble foiling, I think and then simplifying. I got to \[3-6t+3t ^{2}-4+4t+14\]
freckles
  • freckles
I'm confused about the question g(x)=3(1-t)^2-4(1-t)+14 means g(x) is constant unless t is an expression of x
freckles
  • freckles
if g(x)=a where a is constant then g(1-t)=a also

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