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anonymous

  • one year ago

f(x) = 2.5x – 10.5 in this equation, i subtract 2.5 from 10.5, correct? medal and fan! :)

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  1. triciaal
    • one year ago
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    where is the rest of the question?

  2. anonymous
    • one year ago
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    well, it's part of a graph.

  3. triciaal
    • one year ago
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    all you have is the equation. It does not say what to do.

  4. anonymous
    • one year ago
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    i just need to know if i am to subtract 2.5 from 10.

  5. anonymous
    • one year ago
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    i have to complete a table to solve the equation 2.5x - 10.5 = 64(0.5^x)

  6. triciaal
    • one year ago
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    y = f(x) slope = 2.5 and b = -10.5 y = mx + b

  7. anonymous
    • one year ago
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    I don't know if that helps me.

  8. anonymous
    • one year ago
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    need to see the table? so you can see the full problem?

  9. triciaal
    • one year ago
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    from the table what value of x will make the equation true?

  10. anonymous
    • one year ago
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    |dw:1434087863323:dw|

  11. anonymous
    • one year ago
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    |dw:1434088013515:dw|

  12. triciaal
    • one year ago
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    for example when x = 0 on the left f(x) = -10.5 and on the right 64(0.5^x) = 8 -10.5 is not equal to 8 so x = 0 is not a solution

  13. triciaal
    • one year ago
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    ** on the right = 64 -10.5 not = 64 so x = 0 not a solution

  14. triciaal
    • one year ago
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    |dw:1434091798857:dw|

  15. triciaal
    • one year ago
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    replace x with the number and compute

  16. anonymous
    • one year ago
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    they gave me that graph, i can't change the 2. i probably should change the 10 .

  17. triciaal
    • one year ago
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    but do you see how I did x = 0 before I saw the table

  18. triciaal
    • one year ago
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    they want you to do from x = 2 to x = 6

  19. triciaal
    • one year ago
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    since you have the graph maybe you just have to look at the graph and fill in the table

  20. triciaal
    • one year ago
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    the solution is where the graphs intersect

  21. anonymous
    • one year ago
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    okay, but that's not what i'm asking. i'm asking if i am to subtract 2.5 from 10.5 to solve the f(x) equation.

  22. anonymous
    • one year ago
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    thank you for explaining the other stuff though. :)

  23. triciaal
    • one year ago
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    |dw:1434092083535:dw|

  24. triciaal
    • one year ago
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    you have to use the value of x then you can compute. you cannot subtract a number from a variable. you can only add or subtract when you have like terms

  25. triciaal
    • one year ago
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    a term with x is not like a number apples and oranges

  26. triciaal
    • one year ago
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    to directly answer your question no you cannot subtract 10.5 from 2.5 x because they are not like terms.

  27. anonymous
    • one year ago
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    i understand. so do i subtract how do i find the first input on the table?

  28. anonymous
    • one year ago
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    i didn't mean to send the "so do i subtract" part. sorry.

  29. triciaal
    • one year ago
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    I did when x = 0 I did when x = 3 and I did when x = 6 follow along replace the x with 4 and compute fill in the table replace the x with 5 and compute then fill in the table

  30. triciaal
    • one year ago
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    again, the solution is the value of x that gives the same value in the table for f(x) and for g(x)

  31. triciaal
    • one year ago
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    you said you have the graph. the solution is the point where the lines cross/intersect

  32. anonymous
    • one year ago
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    oh, i didn't mean graph earlier, i meant table. the graph comes in later, to check the work.

  33. anonymous
    • one year ago
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    and i'm sorry, but i don't know if i'm following you. so the x in 2.5x - 10.5 is either 2, 3, 4, 5, or 6? and i fill the x in the f(x) and g(x) equations with those numbers until they equal each other?

  34. anonymous
    • one year ago
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    for example: f(x) = 2.5(2) - 10.5 = 5 - 10.5

  35. triciaal
    • one year ago
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    basically yes look again at the drawing see how I did x = 3

  36. anonymous
    • one year ago
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    and: g(x) = 64 (0.5^2) = 64 (.25)

  37. triciaal
    • one year ago
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    the graphs intersect when x = 5

  38. anonymous
    • one year ago
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    so the answer is x = 5?

  39. triciaal
    • one year ago
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    you need to fill in the table

  40. triciaal
    • one year ago
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    you need to fill in the table

  41. anonymous
    • one year ago
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    f(x) = 2.5x - 10.5 = 2.5(2) - 10.5 = 5 - 10.5 = -5.5 correct so far?

  42. triciaal
    • one year ago
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    yes

  43. anonymous
    • one year ago
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    okay. then: g(x) = 64(0.5^x) = 64(0.5^2) = 64(.25) = 16 correct?

  44. anonymous
    • one year ago
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    and for f(x) 2 i would fill in -5.5, and for g(x) 2 i would fill in 16?

  45. triciaal
    • one year ago
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    I can't send the graph as an attachment. when you are finished with the table will send you the link

  46. anonymous
    • one year ago
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    okay so you want me to fill it in on here? i can draw it on here.

  47. triciaal
    • one year ago
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    basically yes the correct notation is f(2) and g(2)

  48. anonymous
    • one year ago
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    okay

  49. triciaal
    • one year ago
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    click on the drawing above and do when x = 4 and x = 5

  50. anonymous
    • one year ago
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    okay

  51. anonymous
    • one year ago
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    0.5^3 would be .125 or 1.25?

  52. anonymous
    • one year ago
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    oh it would be 1.25.

  53. triciaal
    • one year ago
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    no

  54. anonymous
    • one year ago
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    .125?

  55. triciaal
    • one year ago
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    |dw:1434094044119:dw|

  56. triciaal
    • one year ago
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    https://www.desmos.com/calculator

  57. triciaal
    • one year ago
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    so you can input and see the graph

  58. anonymous
    • one year ago
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    oh i understand. so .125.

  59. triciaal
    • one year ago
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    I have to go. I sent the link for the calculator you might want to see the graphs. Intersection is at (5,2) Please review your basic stuff so you can focus on the new material. Always post all of the question so you can get the right help fast. All the best with your studies.

  60. anonymous
    • one year ago
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    |dw:1434091091187:dw|

  61. triciaal
    • one year ago
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    |dw:1434094845878:dw|

  62. anonymous
    • one year ago
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    i know i got it right, so thank you so much for all your help and for dedicating this much of your time to assisting me. i really understand what i'm doing and i enjoy it as well, just like i used to. i really appreciate everything tonight. :)

  63. triciaal
    • one year ago
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    you are welcome

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