anonymous
  • anonymous
f(x) = 2.5x – 10.5 in this equation, i subtract 2.5 from 10.5, correct? medal and fan! :)
Mathematics
chestercat
  • chestercat
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triciaal
  • triciaal
where is the rest of the question?
anonymous
  • anonymous
well, it's part of a graph.
triciaal
  • triciaal
all you have is the equation. It does not say what to do.

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anonymous
  • anonymous
i just need to know if i am to subtract 2.5 from 10.
anonymous
  • anonymous
i have to complete a table to solve the equation 2.5x - 10.5 = 64(0.5^x)
triciaal
  • triciaal
y = f(x) slope = 2.5 and b = -10.5 y = mx + b
anonymous
  • anonymous
I don't know if that helps me.
anonymous
  • anonymous
need to see the table? so you can see the full problem?
triciaal
  • triciaal
from the table what value of x will make the equation true?
anonymous
  • anonymous
|dw:1434087863323:dw|
anonymous
  • anonymous
|dw:1434088013515:dw|
triciaal
  • triciaal
for example when x = 0 on the left f(x) = -10.5 and on the right 64(0.5^x) = 8 -10.5 is not equal to 8 so x = 0 is not a solution
triciaal
  • triciaal
** on the right = 64 -10.5 not = 64 so x = 0 not a solution
triciaal
  • triciaal
|dw:1434091798857:dw|
triciaal
  • triciaal
replace x with the number and compute
anonymous
  • anonymous
they gave me that graph, i can't change the 2. i probably should change the 10 .
triciaal
  • triciaal
but do you see how I did x = 0 before I saw the table
triciaal
  • triciaal
they want you to do from x = 2 to x = 6
triciaal
  • triciaal
since you have the graph maybe you just have to look at the graph and fill in the table
triciaal
  • triciaal
the solution is where the graphs intersect
anonymous
  • anonymous
okay, but that's not what i'm asking. i'm asking if i am to subtract 2.5 from 10.5 to solve the f(x) equation.
anonymous
  • anonymous
thank you for explaining the other stuff though. :)
triciaal
  • triciaal
|dw:1434092083535:dw|
triciaal
  • triciaal
you have to use the value of x then you can compute. you cannot subtract a number from a variable. you can only add or subtract when you have like terms
triciaal
  • triciaal
a term with x is not like a number apples and oranges
triciaal
  • triciaal
to directly answer your question no you cannot subtract 10.5 from 2.5 x because they are not like terms.
anonymous
  • anonymous
i understand. so do i subtract how do i find the first input on the table?
anonymous
  • anonymous
i didn't mean to send the "so do i subtract" part. sorry.
triciaal
  • triciaal
I did when x = 0 I did when x = 3 and I did when x = 6 follow along replace the x with 4 and compute fill in the table replace the x with 5 and compute then fill in the table
triciaal
  • triciaal
again, the solution is the value of x that gives the same value in the table for f(x) and for g(x)
triciaal
  • triciaal
you said you have the graph. the solution is the point where the lines cross/intersect
anonymous
  • anonymous
oh, i didn't mean graph earlier, i meant table. the graph comes in later, to check the work.
anonymous
  • anonymous
and i'm sorry, but i don't know if i'm following you. so the x in 2.5x - 10.5 is either 2, 3, 4, 5, or 6? and i fill the x in the f(x) and g(x) equations with those numbers until they equal each other?
anonymous
  • anonymous
for example: f(x) = 2.5(2) - 10.5 = 5 - 10.5
triciaal
  • triciaal
basically yes look again at the drawing see how I did x = 3
anonymous
  • anonymous
and: g(x) = 64 (0.5^2) = 64 (.25)
triciaal
  • triciaal
the graphs intersect when x = 5
anonymous
  • anonymous
so the answer is x = 5?
triciaal
  • triciaal
you need to fill in the table
triciaal
  • triciaal
you need to fill in the table
anonymous
  • anonymous
f(x) = 2.5x - 10.5 = 2.5(2) - 10.5 = 5 - 10.5 = -5.5 correct so far?
triciaal
  • triciaal
yes
anonymous
  • anonymous
okay. then: g(x) = 64(0.5^x) = 64(0.5^2) = 64(.25) = 16 correct?
anonymous
  • anonymous
and for f(x) 2 i would fill in -5.5, and for g(x) 2 i would fill in 16?
triciaal
  • triciaal
I can't send the graph as an attachment. when you are finished with the table will send you the link
anonymous
  • anonymous
okay so you want me to fill it in on here? i can draw it on here.
triciaal
  • triciaal
basically yes the correct notation is f(2) and g(2)
anonymous
  • anonymous
okay
triciaal
  • triciaal
click on the drawing above and do when x = 4 and x = 5
anonymous
  • anonymous
okay
anonymous
  • anonymous
0.5^3 would be .125 or 1.25?
anonymous
  • anonymous
oh it would be 1.25.
triciaal
  • triciaal
no
anonymous
  • anonymous
.125?
triciaal
  • triciaal
|dw:1434094044119:dw|
triciaal
  • triciaal
https://www.desmos.com/calculator
triciaal
  • triciaal
so you can input and see the graph
anonymous
  • anonymous
oh i understand. so .125.
triciaal
  • triciaal
I have to go. I sent the link for the calculator you might want to see the graphs. Intersection is at (5,2) Please review your basic stuff so you can focus on the new material. Always post all of the question so you can get the right help fast. All the best with your studies.
anonymous
  • anonymous
|dw:1434091091187:dw|
triciaal
  • triciaal
|dw:1434094845878:dw|
anonymous
  • anonymous
i know i got it right, so thank you so much for all your help and for dedicating this much of your time to assisting me. i really understand what i'm doing and i enjoy it as well, just like i used to. i really appreciate everything tonight. :)
triciaal
  • triciaal
you are welcome

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