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can anyone help?
since you know what a is equal to plug its value into the first equation so that you have the first equation only in terms of b, then solve for b
I really dont know
what is a equal to? according to the second equation
thats the thing I dont know:(
if i show you this, z = 10, what is z equal to?
perfect, now if i show you this, a = b − 2, what is a equal to?
a equals 4
a equals b - 2
and be equals 6
no, a equals b - 2
ok lets make sure you understand this, if i show you j = 5i +z - 2, what is j equal to?
5i +z - 2
ok back to your question, so we know a is equal to b - 2
since a is equal to b -2 can you please replace a in the first equation with b -2 since they equal the same thing
ok, b-2 − 3b = 4
now can you solve for b? with that equation b -2 -3b = 4
cna you help me on this one?
to solve for b we need to find out what b equals, so we have an equation that has only numbers and the variable b, so we need to perform some arithmetic on the equation to get b by itself on one side of the equals sign
so lets start by only getting terms with a b in them on one side, so if you have b - 2 - 3b = 4, what would be a good step to take so that there are only terms with b in them on the left side?
how can i get rid of the -2 on the left side?
what happens if we add 2 on both sides of the equation, what do you get?
you get 6
i get 6 on the right hand side of the equals sign but what about on the left side?
b - 2 + 2 - 3b = 4 + 2 b - 2 + 2 - 3b = 6
hey I have a few minutes left to turn this in please help
i am helping, if you just want the answer, i cant do that
I dont but think it is A
good luck bud
ok well thanks
if you change your mind and want to keep working through it let me know
I do :)
ok so we added 2 to both sides to get this b - 2 + 2 - 3b = 4 + 2 b - 2 + 2 - 3b = 6 can you simplify this and tell me what we get?
close, but -2 + 2 is not equal to -4
ohhh sorry got a little confused
ok so -2 + 2 = what?
it eaquals 0
perfect, now we have b + 0 - 3b=6 which equals b - 3b = 6
can you simplify b - 3b = 6 by combining the b terms?
how do I do that
if i have 1b and i take away 3b's how many b's do i have?
do I just do 3b=6???
1b - 3b
so we are almost done we have -2b = 6, now how can you get b by itself?
how can we get rid of the -2?
turn it into a 1
by adding 2 on both sides
by dividing both sides by -2
yes thats what I meant lol
-2/-2 = 1 so (-2b)/-2 = 6/(-2) 1b = 6/(-2) b = 6 / (-2)
so what is 6 / (-2), 6 divided by -2
perfect, so b = -3, so now you know the answer, do you see an answer where the second number is -3? (a, b) (a, -3)
which one is it?
we can find a very easily also looking at the second equation we have a = b - 2 so if i plug in b i get a = -3 -2
so it is D?
yay thanks so much
you're welcome, please do some practice on this stuff or your future classes in college will be very difficult, visit khan academy and get help on here and other sites also
have a good day
nice to see too much long conversation in such a simple question