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anonymous

  • one year ago

mDE=111 and mBC= 64 find m<a

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  1. anonymous
    • one year ago
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    |dw:1434089151213:dw|

  2. anonymous
    • one year ago
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    @ganeshie8

  3. anonymous
    • one year ago
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    What kind of problem is this?

  4. anonymous
    • one year ago
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    Like what are they called lol

  5. anonymous
    • one year ago
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    Secants that are intersecting outside the circle

  6. anonymous
    • one year ago
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    and DE and BC arc labeled as arcs i just couldn't put the sign above them

  7. anonymous
    • one year ago
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    @alanabrisa

  8. anonymous
    • one year ago
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    gotcha, give me one sec

  9. anonymous
    • one year ago
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    ok thank you :)

  10. anonymous
    • one year ago
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    Is 111 that degree angle?

  11. ganeshie8
    • one year ago
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    you may use below formula |dw:1434089557341:dw|

  12. anonymous
    • one year ago
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    arc @alanabrisa

  13. anonymous
    • one year ago
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    So the formula for this is simple. You have m<a = 111-64/2

  14. anonymous
    • one year ago
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    Do you think you can solve it?

  15. anonymous
    • one year ago
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    79

  16. ganeshie8
    • one year ago
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    |dw:1434089659765:dw|

  17. anonymous
    • one year ago
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    thank you very much i got the answer :)

  18. ganeshie8
    • one year ago
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    79 is not right

  19. anonymous
    • one year ago
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    You might have miscalculated

  20. ganeshie8
    • one year ago
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    \[m\angle A ~~=~~\dfrac{111-64}{2}~~=?\]

  21. anonymous
    • one year ago
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    oh oops its 23.5

  22. anonymous
    • one year ago
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    Good job! :)

  23. anonymous
    • one year ago
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    thanks for the help

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spraguer (Moderator)
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