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anonymous

  • one year ago

Help please???? What is the equation of a parabola with vertex (0, 0) and a focus at (2, 0).

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  1. anonymous
    • one year ago
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    you can tag some of the qualified helpers to help you on this question. :) you can find them by clicking the grey button under the orange button that says "rate a qualified helper", then click qualified helpers, then tag those names in the comments on your post.

  2. campbell_st
    • one year ago
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    what is the distance from the vertex to the focus..?

  3. anonymous
    • one year ago
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    2?

  4. campbell_st
    • one year ago
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    great that distance is called the focal length the focus is to the right of the vertex so the parabola is concave right |dw:1434090472682:dw| so a general form of this parabola is \[(y - k)^2 = 4a(x - h)\] where (h, k) is the vertex and a is the focal length... so any thoughts on the equation... after you substitute what you know...?

  5. campbell_st
    • one year ago
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    you have a vertext (0,0) and a focal length a = 2

  6. anonymous
    • one year ago
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    So the equation is (y-0)^2=4(2)(x-0)? what do I do next?

  7. campbell_st
    • one year ago
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    just simplify it \[y^2 = 8x\]

  8. anonymous
    • one year ago
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    Okay thank you!!

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