anonymous
  • anonymous
Help please???? What is the equation of a parabola with vertex (0, 0) and a focus at (2, 0).
Mathematics
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anonymous
  • anonymous
Help please???? What is the equation of a parabola with vertex (0, 0) and a focus at (2, 0).
Mathematics
chestercat
  • chestercat
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
you can tag some of the qualified helpers to help you on this question. :) you can find them by clicking the grey button under the orange button that says "rate a qualified helper", then click qualified helpers, then tag those names in the comments on your post.
campbell_st
  • campbell_st
what is the distance from the vertex to the focus..?
anonymous
  • anonymous
2?

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campbell_st
  • campbell_st
great that distance is called the focal length the focus is to the right of the vertex so the parabola is concave right |dw:1434090472682:dw| so a general form of this parabola is \[(y - k)^2 = 4a(x - h)\] where (h, k) is the vertex and a is the focal length... so any thoughts on the equation... after you substitute what you know...?
campbell_st
  • campbell_st
you have a vertext (0,0) and a focal length a = 2
anonymous
  • anonymous
So the equation is (y-0)^2=4(2)(x-0)? what do I do next?
campbell_st
  • campbell_st
just simplify it \[y^2 = 8x\]
anonymous
  • anonymous
Okay thank you!!

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