What is the equation of a parabola with vertex (0, 0) and a focus at (2, 0).
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
you can tag some of the qualified helpers to help you on this question. :) you can find them by clicking the grey button under the orange button that says "rate a qualified helper", then click qualified helpers, then tag those names in the comments on your post.
what is the distance from the vertex to the focus..?
Not the answer you are looking for? Search for more explanations.
great that distance is called the focal length
the focus is to the right of the vertex so the parabola is concave right
so a general form of this parabola is
\[(y - k)^2 = 4a(x - h)\]
where (h, k) is the vertex and a is the focal length...
so any thoughts on the equation... after you substitute what you know...?
you have a vertext (0,0) and a focal length a = 2
So the equation is (y-0)^2=4(2)(x-0)? what do I do next?