anonymous
  • anonymous
Help please???? What is the equation of a parabola with vertex (0, 0) and a focus at (2, 0).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
you can tag some of the qualified helpers to help you on this question. :) you can find them by clicking the grey button under the orange button that says "rate a qualified helper", then click qualified helpers, then tag those names in the comments on your post.
campbell_st
  • campbell_st
what is the distance from the vertex to the focus..?
anonymous
  • anonymous
2?

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campbell_st
  • campbell_st
great that distance is called the focal length the focus is to the right of the vertex so the parabola is concave right |dw:1434090472682:dw| so a general form of this parabola is \[(y - k)^2 = 4a(x - h)\] where (h, k) is the vertex and a is the focal length... so any thoughts on the equation... after you substitute what you know...?
campbell_st
  • campbell_st
you have a vertext (0,0) and a focal length a = 2
anonymous
  • anonymous
So the equation is (y-0)^2=4(2)(x-0)? what do I do next?
campbell_st
  • campbell_st
just simplify it \[y^2 = 8x\]
anonymous
  • anonymous
Okay thank you!!

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