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anonymous
 one year ago
pleeeeeeeeeeeeaaaaaaaase helllllp me..........
a certain machine make matches. one match in 10000 on average is defective. using a suitable approximation, find the probability that a random sample of 45000 matches will include 2, 3 or 4 defective matches
anonymous
 one year ago
pleeeeeeeeeeeeaaaaaaaase helllllp me.......... a certain machine make matches. one match in 10000 on average is defective. using a suitable approximation, find the probability that a random sample of 45000 matches will include 2, 3 or 4 defective matches

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yesss.. actually am learning poisson distribution

alekos
 one year ago
Best ResponseYou've already chosen the best response.1P(2 defects) = P(1 defect) x P(1 defect) P(3 defects) = P(2 defects) x P(1 defect) P(4 defects) = P(3 defects) x P( 1 defect)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would you calculate them ?

alekos
 one year ago
Best ResponseYou've already chosen the best response.1P(2 or 3 or 4 defects) = P(2 defects) + P(3 defects) + P(4 defects)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0help me with the numbers

alekos
 one year ago
Best ResponseYou've already chosen the best response.1well you already know that P(1 defect) = 1/10000 so from there it is just simple arithmetic

alekos
 one year ago
Best ResponseYou've already chosen the best response.1use your calculator in exponential or scientific mode

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you sure its simple arithmetic ? hve u calculated ?

alekos
 one year ago
Best ResponseYou've already chosen the best response.1Approximately \[\frac{ 1 }{ 10^{8} }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0its wrong.. the answer should be 0.471 its not simple arithmetic

alekos
 one year ago
Best ResponseYou've already chosen the best response.1can you send me a photo of the actual question?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it is the actual question

alekos
 one year ago
Best ResponseYou've already chosen the best response.1That figure is not possible based on the information you have given

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1i can help you but not whilst others are as that is counter productive for all concerned tag me later

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know poisson distribution ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1yes and the answer is 0.471004095.......

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1start with the formula and work out \( \lambda \). have you done that? expected outcome given failure rate of 1/10000

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1then just plug in as per @alekos suggestion ie P(2 or 3 or 4 defects) = P(2 defects) + P(3 defects) + P(4 defects) but what is your \( \lambda\)? that's all that's missing

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1\( \lambda\) is how many you would expect to be defective in a lot of 45,000 given failure rate 1/10,000 then \( P(X=2) = \frac{e^{ \lambda } \lambda^2}{2!}\) do same for 3 and 4 and add and you're done

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1i have to go but here are the numbers you should get 2 0.11247859 3 0.168717885 4 0.189807621 \(\Sigma\) 0.471004095
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