Prove

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

\(\large \color{black}{\begin{align} & \normalsize \text{Prove the area of the region enclosed by the graph }\hspace{.33em}\\~\\ & y=-|x\pm k|+5,y=0\hspace{.33em}\\~\\ & \normalsize \text{ is constant for} \ \ k,\ k\in \mathbb{R}\ \hspace{.33em}\\~\\ \end{align}}\)
I'm finding it hard to visualize... could you show the area in graph ?
https://www.desmos.com/calculator/ylkcvfm5ss

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Ahh that should be easy
First of all, we acknowledge that the the absolute value gives the distance between two points on number line: |dw:1434119749216:dw|
You can prove it using calculus. The integral of that is constant.
In light that of above thing, \(|x-k|\) represents the distance between \(x\) and \(k\).
Set the given function equal to \(0\) and solve \(x\) intercepts : \[-|x-k|+5=0 \implies |x-k|=5\]
x=5+k.-5+k
Yes, subtract them to get the base of triangle
base->10
|dw:1434120100063:dw|
ok thnx

Not the answer you are looking for?

Search for more explanations.

Ask your own question