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anonymous

  • one year ago

y=e^sqrt(x)) x=1 Evaluate dy/dx, meaning they want me to use chain rule, but I cant get the right answer, help!!

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  1. johnweldon1993
    • one year ago
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    \[\large \frac{dy}{dx} = \frac{d(e^{\sqrt{x}})}{dx}\] The chain rule says...take the derivative of the inside...and multiply it to the derivative of the outside... Take the "inside" to be \(\large \sqrt{x} \)

  2. johnweldon1993
    • one year ago
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    So if we treat \(\large u = \sqrt{x}\) ... then \(\large y = e^{u}\) So the derivative of \(\large \sqrt{x}\) is \(\large \frac{1}{2\sqrt{x}}\) and the derivative of \(\large e^{u} = e^{u}\) So when you multiply them together you get \[\large \frac{e^{u}}{2\sqrt{x}}\] But of course you want to go back and replace what 'u' was...so our final answer would be \[\large \frac{e^{\sqrt{x}}}{2\sqrt{x}}\]

  3. anonymous
    • one year ago
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    So simple but somehow I managed to mess this on up, maybe the fact that Ive been studying since 6 am and now its almost 4 pm. Thanks!

  4. johnweldon1993
    • one year ago
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    Lol yeah after 2 hours I'm all set...should probably take a break!

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