A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
y=e^sqrt(x)) x=1
Evaluate dy/dx, meaning they want me to use chain rule, but I cant get the right answer, help!!
anonymous
 one year ago
y=e^sqrt(x)) x=1 Evaluate dy/dx, meaning they want me to use chain rule, but I cant get the right answer, help!!

This Question is Closed

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1\[\large \frac{dy}{dx} = \frac{d(e^{\sqrt{x}})}{dx}\] The chain rule says...take the derivative of the inside...and multiply it to the derivative of the outside... Take the "inside" to be \(\large \sqrt{x} \)

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1So if we treat \(\large u = \sqrt{x}\) ... then \(\large y = e^{u}\) So the derivative of \(\large \sqrt{x}\) is \(\large \frac{1}{2\sqrt{x}}\) and the derivative of \(\large e^{u} = e^{u}\) So when you multiply them together you get \[\large \frac{e^{u}}{2\sqrt{x}}\] But of course you want to go back and replace what 'u' was...so our final answer would be \[\large \frac{e^{\sqrt{x}}}{2\sqrt{x}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So simple but somehow I managed to mess this on up, maybe the fact that Ive been studying since 6 am and now its almost 4 pm. Thanks!

johnweldon1993
 one year ago
Best ResponseYou've already chosen the best response.1Lol yeah after 2 hours I'm all set...should probably take a break!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.