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anonymous

  • one year ago

A and B are vertical angles. If A = 4x - 10 and B = 6x - 30, find mA.

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  1. Nnesha
    • one year ago
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    pic ??

  2. Nnesha
    • one year ago
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    vertical angles are equal

  3. anonymous
    • one year ago
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    There is no picture.

  4. Nnesha
    • one year ago
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    alright so a and b are vertical angles vertical angles share the same vertex |dw:1434116295080:dw| for example here ^^^ a = b c=d a and are vertical angles and c and d are vertical equal so they are equal to each other \[\huge\rm 4x-10=6x-30\] solve for x

  5. anonymous
    • one year ago
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    So when I solve 4x-10 i get 2.5 and when i solve 6x-30 i get 5.

  6. Nnesha
    • one year ago
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    wait what ? how did you get 2.5 and why did you solve it separately ?

  7. anonymous
    • one year ago
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    I divided 10 by 4 & i got 2.5

  8. Nnesha
    • one year ago
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    no no no! 4x MINUS 10 you can't divide by 10

  9. Nnesha
    • one year ago
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    write all x value to the one side of equal sign and constant term to the other side *constant term (number without variable )

  10. Nnesha
    • one year ago
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    \[\huge\rm 4x-10=6x-30\] subtract 4x both sides

  11. anonymous
    • one year ago
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    There is a theorem that states two vertical angles are congruent, i.e. have the same angle measure. Thus A = B. Substituting in the values we have for A and B you get a linear equation that can be solved to find x. 4x - 10 = 6x - 30 -10 = 2x - 30 20 = 2x 10 = x Now that we know x, substitute back into the expression for A. A = 4x - 10 = 4*10 - 10 = 40 - 10 = 30 mA = 30

  12. anonymous
    • one year ago
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    Thank you.

  13. Nnesha
    • one year ago
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    remember to cancel out addition === >opposite subtraction multiplication ===> opposite division

  14. Nnesha
    • one year ago
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    so to cancel 4x from left side you should subtract 4x both sides :-)

  15. Nnesha
    • one year ago
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    |dw:1434117089054:dw| let me know what you get

  16. anonymous
    • one year ago
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    x=20

  17. Nnesha
    • one year ago
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    how did you get 20 please show your work so i can find your mistake :-)

  18. anonymous
    • one year ago
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    |dw:1434117408586:dw|

  19. anonymous
    • one year ago
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    |dw:1434117516941:dw|

  20. Nnesha
    • one year ago
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    alright thanks! and combine like terms are add or subtract coefficient of SAME varaible 6x-30 <--- you can't subtract because 6 have x and 30 doesn't have x |dw:1434117600094:dw| there is NEGATIVE 30 at right side how would you move that to the left side ???

  21. Nnesha
    • one year ago
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    add or subtract 30 both sides ?

  22. anonymous
    • one year ago
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    add.

  23. Nnesha
    • one year ago
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    yep add 30 both sides |dw:1434117716411:dw| still... we have to isolate x so how would you cancel out 2 from the right side ?? :-)

  24. anonymous
    • one year ago
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    |dw:1434117733194:dw|

  25. Nnesha
    • one year ago
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    yep yep divide! you got it!! so x = ??

  26. anonymous
    • one year ago
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    x=10

  27. Nnesha
    • one year ago
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    yep now be careful x=10 but they want us to find A so substitute x value in this equation \[\large\rm A =4x-10\]

  28. anonymous
    • one year ago
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    so the answer is A=10? lol i dont know

  29. Nnesha
    • one year ago
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    nope x=10 you need mA so replace x by 10 A=4x-10 and then solve for A

  30. Nnesha
    • one year ago
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    \[\huge\rm A=4\color{green}{x}-10\] plug in 10

  31. anonymous
    • one year ago
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    |dw:1434118220477:dw|

  32. Nnesha
    • one year ago
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    :-)yaya!

  33. anonymous
    • one year ago
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    i get it!

  34. Nnesha
    • one year ago
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    yeah :-)gO_Od job!

  35. anonymous
    • one year ago
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    Lol thank you.

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