anonymous
  • anonymous
A and B are vertical angles. If A = 4x - 10 and B = 6x - 30, find mA.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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Nnesha
  • Nnesha
pic ??
Nnesha
  • Nnesha
vertical angles are equal
anonymous
  • anonymous
There is no picture.

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Nnesha
  • Nnesha
alright so a and b are vertical angles vertical angles share the same vertex |dw:1434116295080:dw| for example here ^^^ a = b c=d a and are vertical angles and c and d are vertical equal so they are equal to each other \[\huge\rm 4x-10=6x-30\] solve for x
anonymous
  • anonymous
So when I solve 4x-10 i get 2.5 and when i solve 6x-30 i get 5.
Nnesha
  • Nnesha
wait what ? how did you get 2.5 and why did you solve it separately ?
anonymous
  • anonymous
I divided 10 by 4 & i got 2.5
Nnesha
  • Nnesha
no no no! 4x MINUS 10 you can't divide by 10
Nnesha
  • Nnesha
write all x value to the one side of equal sign and constant term to the other side *constant term (number without variable )
Nnesha
  • Nnesha
\[\huge\rm 4x-10=6x-30\] subtract 4x both sides
anonymous
  • anonymous
There is a theorem that states two vertical angles are congruent, i.e. have the same angle measure. Thus A = B. Substituting in the values we have for A and B you get a linear equation that can be solved to find x. 4x - 10 = 6x - 30 -10 = 2x - 30 20 = 2x 10 = x Now that we know x, substitute back into the expression for A. A = 4x - 10 = 4*10 - 10 = 40 - 10 = 30 mA = 30
anonymous
  • anonymous
Thank you.
Nnesha
  • Nnesha
remember to cancel out addition === >opposite subtraction multiplication ===> opposite division
Nnesha
  • Nnesha
so to cancel 4x from left side you should subtract 4x both sides :-)
Nnesha
  • Nnesha
|dw:1434117089054:dw| let me know what you get
anonymous
  • anonymous
x=20
Nnesha
  • Nnesha
how did you get 20 please show your work so i can find your mistake :-)
anonymous
  • anonymous
|dw:1434117408586:dw|
anonymous
  • anonymous
|dw:1434117516941:dw|
Nnesha
  • Nnesha
alright thanks! and combine like terms are add or subtract coefficient of SAME varaible 6x-30 <--- you can't subtract because 6 have x and 30 doesn't have x |dw:1434117600094:dw| there is NEGATIVE 30 at right side how would you move that to the left side ???
Nnesha
  • Nnesha
add or subtract 30 both sides ?
anonymous
  • anonymous
add.
Nnesha
  • Nnesha
yep add 30 both sides |dw:1434117716411:dw| still... we have to isolate x so how would you cancel out 2 from the right side ?? :-)
anonymous
  • anonymous
|dw:1434117733194:dw|
Nnesha
  • Nnesha
yep yep divide! you got it!! so x = ??
anonymous
  • anonymous
x=10
Nnesha
  • Nnesha
yep now be careful x=10 but they want us to find A so substitute x value in this equation \[\large\rm A =4x-10\]
anonymous
  • anonymous
so the answer is A=10? lol i dont know
Nnesha
  • Nnesha
nope x=10 you need mA so replace x by 10 A=4x-10 and then solve for A
Nnesha
  • Nnesha
\[\huge\rm A=4\color{green}{x}-10\] plug in 10
anonymous
  • anonymous
|dw:1434118220477:dw|
Nnesha
  • Nnesha
:-)yaya!
anonymous
  • anonymous
i get it!
Nnesha
  • Nnesha
yeah :-)gO_Od job!
anonymous
  • anonymous
Lol thank you.

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