A and B are vertical angles. If A = 4x - 10 and B = 6x - 30, find mA.

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A and B are vertical angles. If A = 4x - 10 and B = 6x - 30, find mA.

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alright so a and b are vertical angles vertical angles share the same vertex |dw:1434116295080:dw| for example here ^^^ a = b c=d a and are vertical angles and c and d are vertical equal so they are equal to each other \[\huge\rm 4x-10=6x-30\] solve for x
So when I solve 4x-10 i get 2.5 and when i solve 6x-30 i get 5.
wait what ? how did you get 2.5 and why did you solve it separately ?
I divided 10 by 4 & i got 2.5
no no no! 4x MINUS 10 you can't divide by 10
write all x value to the one side of equal sign and constant term to the other side *constant term (number without variable )
\[\huge\rm 4x-10=6x-30\] subtract 4x both sides
There is a theorem that states two vertical angles are congruent, i.e. have the same angle measure. Thus A = B. Substituting in the values we have for A and B you get a linear equation that can be solved to find x. 4x - 10 = 6x - 30 -10 = 2x - 30 20 = 2x 10 = x Now that we know x, substitute back into the expression for A. A = 4x - 10 = 4*10 - 10 = 40 - 10 = 30 mA = 30
Thank you.
remember to cancel out addition === >opposite subtraction multiplication ===> opposite division
so to cancel 4x from left side you should subtract 4x both sides :-)
|dw:1434117089054:dw| let me know what you get
x=20
how did you get 20 please show your work so i can find your mistake :-)
|dw:1434117408586:dw|
|dw:1434117516941:dw|
alright thanks! and combine like terms are add or subtract coefficient of SAME varaible 6x-30 <--- you can't subtract because 6 have x and 30 doesn't have x |dw:1434117600094:dw| there is NEGATIVE 30 at right side how would you move that to the left side ???
add or subtract 30 both sides ?
add.
yep add 30 both sides |dw:1434117716411:dw| still... we have to isolate x so how would you cancel out 2 from the right side ?? :-)
|dw:1434117733194:dw|
yep yep divide! you got it!! so x = ??
x=10
yep now be careful x=10 but they want us to find A so substitute x value in this equation \[\large\rm A =4x-10\]
so the answer is A=10? lol i dont know
nope x=10 you need mA so replace x by 10 A=4x-10 and then solve for A
\[\huge\rm A=4\color{green}{x}-10\] plug in 10
|dw:1434118220477:dw|
:-)yaya!
i get it!
yeah :-)gO_Od job!
Lol thank you.

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