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anonymous
 one year ago
Simplify secθ + secθtan^2θ.
A.) 1
B.) cosθ
C.) secθ
D.) sec^3θ
anonymous
 one year ago
Simplify secθ + secθtan^2θ. A.) 1 B.) cosθ C.) secθ D.) sec^3θ

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4sec theta = x tan theta = y so you can write it as \[\huge\rm (x+xy^2)\] so what is common in these both terms ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes right so take it out\[\huge\rm x(1+y^2)\] now you can replace x and y by sec an tan \[\huge\rm sec \theta (1+ \tan^2)\] 1+tan^2 = what ? ^^^^identity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i still dont understand whatsoever.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4it's same like simple algebra first we have to find GCF(greatest common factor) \[\huge\rm sec \theta + \sec \theta \tan^2 \] sec is common so take it out and divide both terms by common factor write your answer in the parenthesesdw:1434120062504:dw \[\sec \theta (1+ tan^2 \theta )\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right now i feel like i must be missing something... because i dont understand what i am susposed to be understanding...

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4alright did you take notes ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4tag other users maybe they can explain better than me :) :) good luck!!! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@aloud @mathmath333 @mathmate

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2As @Nnesha said, factor: secθ + secθtan^2θ what do you get?

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2For example, factoring xy+xz = x(y+z)

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2You take out the common factor from each term. It's like the inverse of distribution.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0right now, i guess my mind is still waking up. but i think i am starting to understand factoring...

mathmate
 one year ago
Best ResponseYou've already chosen the best response.2Well, hints I give would be: 1. factor out sec\(\theta\) see https://www.mathsisfun.com/algebra/factoring.html for help 2. apply one of the pythagorean trig. identities. see http://www.sosmath.com/trig/Trig5/trig5/trig5.html for help.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4Practice does not make perfect. Only \(\huge\rm \color{reD}{{Perfect~Practice}}\) makes perfect. ~Vince Lombardi so practice!!
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