## anonymous one year ago Trig/ Pre Cal. How do I do this? I need to work out these using Trig identities $$tan^2 + 5 = sec^2 + 4$$ $$\frac{sin^2}{cos^2} + 5 = sec^2 + 4$$ Am I on the right path? What should I do next?

1. Nnesha

well....i think we can write 5 as 1+4

2. Nnesha

$\huge\rm tan^2 +5 = \tan^2 +1+4$ like this then use this identity 1+tan^2 = sec^2

3. Nnesha

i guess.....

4. anonymous

$$\frac{1-cos^2}{1-sin^2} + 5 = sec^2 + 4$$ Is this the right path? How do I get the left side to = $$sec^2 + 4$$

5. Nnesha

if you do the other way like i did tan^2 +1+4 now you can apply this identity (1+tan^2) =sec^2 = done! 2 steps

6. anonymous

tan^2+1+4 = tan^2+5 but I need tan^2 + 5 to equal sec^2+4 How does tan^2 become sec^2? Only 1+tan^2 = sec^2

7. Nnesha

yes that's right that's why i wrote 1+4 instead 5 now you can apply that identity$\huge\rm \color{reD}{tan^2 +1}+4 = sec^2 +4$

8. Nnesha

tan^2 + 1 is same as 1+tan^2 $\huge\rm \color{reD}{1+tan^2 }+4 = sec^2 +4$

9. anonymous

I have tan^2 on the left said. You are saying tan^2 = 1+tan^2. You just through out tan^2 and put in 1+ tan^2 but tan^2 does not = 1+tan^2

10. Nnesha

nope i never said that tan^2 = 1+tan^2 well start it again $\huge\rm tan^2 +5$ is same as $\tan^2 +1+4$ agree or no ??

11. Nnesha

1+4 =5 you can write 5 as 1+4

12. anonymous

AH I see!!! Man that was right in front of me.. I was way over thinking this thing lol

13. Nnesha

yaya!!! :-)

14. Nnesha

i can understand i guess helping other users and PRACTICE help me to find out easy way :-)

15. Nnesha

just practice practice and practice :-)

16. anonymous

Thank you for showing me the light :-)

17. Nnesha

haha my pleasure!!! :-)