anonymous
  • anonymous
A triangular lot bounded by three streets has a length of 300 feet on one street, 250 feet on the second, and 420 feet on the third. Find the measure of the largest angle formed by these streets. Which of the following equations can be used to solve the problem?
Geometry
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anonymous
  • anonymous
A triangular lot bounded by three streets has a length of 300 feet on one street, 250 feet on the second, and 420 feet on the third. Find the measure of the largest angle formed by these streets. Which of the following equations can be used to solve the problem?
Geometry
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
looks like a law of cosines problem. The largest angle is opposite the longest side
anonymous
  • anonymous
thanks
P0sitr0n
  • P0sitr0n
still need help?

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anonymous
  • anonymous
yea..... idk how to do this, i know that the equation is\[c^2=a^2+b^2-2ab(cosC)\] but i don't know how to apply it.
anonymous
  • anonymous
|dw:1434124669566:dw| Let's say this is our triangle a, b, and c are the lengths and A, B, C are angles
anonymous
  • anonymous
420² = 300² + 250² - 300(250) cos Θ
anonymous
  • anonymous
do you see where all the substitutions came from?
anonymous
  • anonymous
Yes I do!!!!!! Thanks @peachpi

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