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anonymous

  • one year ago

A triangular lot bounded by three streets has a length of 300 feet on one street, 250 feet on the second, and 420 feet on the third. Find the measure of the largest angle formed by these streets. Which of the following equations can be used to solve the problem?

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  1. anonymous
    • one year ago
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    looks like a law of cosines problem. The largest angle is opposite the longest side

  2. anonymous
    • one year ago
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    thanks

  3. P0sitr0n
    • one year ago
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    still need help?

  4. anonymous
    • one year ago
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    yea..... idk how to do this, i know that the equation is\[c^2=a^2+b^2-2ab(cosC)\] but i don't know how to apply it.

  5. anonymous
    • one year ago
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    |dw:1434124669566:dw| Let's say this is our triangle a, b, and c are the lengths and A, B, C are angles

  6. anonymous
    • one year ago
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    420² = 300² + 250² - 300(250) cos Θ

  7. anonymous
    • one year ago
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    do you see where all the substitutions came from?

  8. anonymous
    • one year ago
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    Yes I do!!!!!! Thanks @peachpi

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