If 8p = -2X2 - 100, which of the following could X possibly be?

- anonymous

If 8p = -2X2 - 100, which of the following could X possibly be?

- chestercat

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- misty1212

HI!!

- misty1212

is it
\[8p=-2x^2-100\]?

- anonymous

Yes mam!

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## More answers

- misty1212

so i guess your job is to solve for \(x\) right?

- anonymous

Thanks for the help @misty1212 greatly appreciate it. And yes find X

- misty1212

maybe start with
\[8p+100=-2x^2\] then divide by \(-2\) and get
\[-4p-50=x^2\]

- misty1212

last step would be to take the square root and get
\[x=\pm\sqrt{-4p-50}\]

- anonymous

That's not a answer choice :9 This is so confusing.

- misty1212

can you post a screen shot?

- misty1212

or give the choices?

- anonymous

x = -8p - 100 over 2

- anonymous

How did you get that!?

- misty1212

it it wrong
we need a screen shot or sommat

- anonymous

http://gyazo.com/0238f2b09b590917c2e11614eaf83973

- misty1212

lol the idiots did not bother to divide by 2!!!

- misty1212

go with C

- anonymous

Thanks!!! Few more?

- misty1212

sure i hope they get better

- anonymous

Solve 3x2 + x + 10 = 0. Round solutions to the nearest hundredth.
I got no real solutions but idk.

- misty1212

no real solution looks good

- anonymous

shes right

- anonymous

Thanks @LesTwins

- anonymous

Derek kicks a soccer ball off the ground and in the air, with an initial velocity of 31 feet per second. Using the formula H(t) = -16t2 + vt + s, what is the maximum height the soccer ball reaches?

- misty1212

is it really 31, or could it be 32?

- anonymous

idk -_- @satellite73

- misty1212

i am asking if you made a typo is all
it would be tons easier if it was "initial velocity of 32" instead of "31"

- anonymous

31

- misty1212

ok then if it is 31 it is 31
first coordinate of the vertex of \(y=ax^2+bx+c\) is \(-\frac{b}{2a}\) which, in your case, is
\[-\frac{31}{2\times( -16)}=\frac{31}{32}\]

- misty1212

if it was initial velocity of 32 you would get a 1, which would be a lot easier to deal with, but whatever
now you have to compute
\[h(\frac{31}{32})\]

- misty1212

i would use a calculator
http://www.wolframalpha.com/input/?i=-16%2831%2F32%29%5E2%2B31%2831%2F32%29

- anonymous

at max height H(t)=0
-32t+v=0
t=v/32
t=31/32
H(31/32)=-16(31/32)^2+31*31/32
= 15

- anonymous

tahnks <3

- anonymous

Last one
A toy rocket was launched from the ground. The function f(x) = -16x2 + 128x shows the height of the rocket f(x), in feet, from the ground at time x seconds. What is the axis of symmetry of the graph of f(x), and what does it represent?

- anonymous

@satellite73 pls

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