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anonymous
 one year ago
If 8p = 2X2  100, which of the following could X possibly be?
anonymous
 one year ago
If 8p = 2X2  100, which of the following could X possibly be?

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.0is it \[8p=2x^2100\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0so i guess your job is to solve for \(x\) right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks for the help @misty1212 greatly appreciate it. And yes find X

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0maybe start with \[8p+100=2x^2\] then divide by \(2\) and get \[4p50=x^2\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0last step would be to take the square root and get \[x=\pm\sqrt{4p50}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That's not a answer choice :9 This is so confusing.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0can you post a screen shot?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0or give the choices?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x = 8p  100 over 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0How did you get that!?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0it it wrong we need a screen shot or sommat

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0lol the idiots did not bother to divide by 2!!!

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0sure i hope they get better

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Solve 3x2 + x + 10 = 0. Round solutions to the nearest hundredth. I got no real solutions but idk.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0no real solution looks good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Derek kicks a soccer ball off the ground and in the air, with an initial velocity of 31 feet per second. Using the formula H(t) = 16t2 + vt + s, what is the maximum height the soccer ball reaches?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0is it really 31, or could it be 32?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk _ @satellite73

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0i am asking if you made a typo is all it would be tons easier if it was "initial velocity of 32" instead of "31"

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0ok then if it is 31 it is 31 first coordinate of the vertex of \(y=ax^2+bx+c\) is \(\frac{b}{2a}\) which, in your case, is \[\frac{31}{2\times( 16)}=\frac{31}{32}\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0if it was initial velocity of 32 you would get a 1, which would be a lot easier to deal with, but whatever now you have to compute \[h(\frac{31}{32})\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0i would use a calculator http://www.wolframalpha.com/input/?i=16%2831%2F32%29%5E2%2B31%2831%2F32%29

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0at max height H(t)=0 32t+v=0 t=v/32 t=31/32 H(31/32)=16(31/32)^2+31*31/32 = 15

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Last one A toy rocket was launched from the ground. The function f(x) = 16x2 + 128x shows the height of the rocket f(x), in feet, from the ground at time x seconds. What is the axis of symmetry of the graph of f(x), and what does it represent?
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