write an equation in the form y= mx+b for the line that has a slope of -5 and contains the point (7,0)

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write an equation in the form y= mx+b for the line that has a slope of -5 and contains the point (7,0)

Mathematics
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\[\huge~y-y_1=m(x-x_1)\] m=slope (x1,y1)
So you have m in the equation which is the slope. thus you have y = -5x+ b now you need to solve for b. to do this take the y coordinate (0) and plug in to the equation and plug the x coordinate into the equation yielding -> 0 = -5(7) + b <- now solve for b. then you now can put it back into the form of y = mx + b
so i multiply -5 from 7 will equal -35

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right. now solve for b .
how do i solve for b
so you found -35 right which is m*x in the equation y = mx + b you already have 0 for y meaning 0 = -35 + b you now need to isolate b which means b = what?
b=-35
not quite.
|dw:1434129642648:dw| does that make sense?
ok so take out the negative
yes because you need to move the -35 to the other side. Now you have m and you have b so you plug backinto the formula to create the equation. y = mx +b -> y = -5x + 35

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