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chris215

  • one year ago

An airplane leaves an airport and flies due west 150 miles and then 170 miles in the direction S 49.17°W. How far is the plane from the airport (round to the nearest mile)?

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  1. chris215
    • one year ago
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    |dw:1434130266939:dw|

  2. chris215
    • one year ago
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    i know that 90 + 49.17 = 139.17

  3. chris215
    • one year ago
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    now do I use c^2=a^2+b^2?

  4. anonymous
    • one year ago
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    90 + 49.17

  5. chris215
    • one year ago
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    yeah is that all i need to do?

  6. anonymous
    • one year ago
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    |dw:1434142811182:dw|

  7. chris215
    • one year ago
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    = 150^2 + 170^2 - 2(150)(170cos)(139.17) = 226 miles

  8. anonymous
    • one year ago
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    angle as i have shown in the figure angle is (180-49.17)

  9. anonymous
    • one year ago
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    \[\cos (180-49.17)=-\cos 49.17\]

  10. anonymous
    • one year ago
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    \[- \cos 49.17=\frac{ 150^2+170^2-OB^2 }{ 2*150*170 }\]

  11. anonymous
    • one year ago
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    \[5100 *(-\cos 49.17)=22500+28900-OB^2\]

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