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lynda.boyce
 one year ago
Ok, I'm not sure if I am doing this problem right. Let G(x)=5/(x2)^2. Find the lim x 2 G(x). I used 2 in the equation. so I got G(x)=5/(22)^2. the answer comes up as undefined.
lynda.boyce
 one year ago
Ok, I'm not sure if I am doing this problem right. Let G(x)=5/(x2)^2. Find the lim x 2 G(x). I used 2 in the equation. so I got G(x)=5/(22)^2. the answer comes up as undefined.

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misty1212
 one year ago
Best ResponseYou've already chosen the best response.1it is really \[\lim_{x\to 2}\frac{5}{(x2)^2}\]?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.1then since the denominator goes to zero and the numerator does not, there is no limit

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0Doesn't the deniminator approach zero but not gat there so the limit is infinity.?

lynda.boyce
 one year ago
Best ResponseYou've already chosen the best response.0thank you @misty1212
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