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lynda.boyce

  • one year ago

Ok, I'm not sure if I am doing this problem right. Let G(x)=5/(x-2)^2. Find the lim x 2 G(x). I used 2 in the equation. so I got G(x)=5/(2-2)^2. the answer comes up as undefined.

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  1. misty1212
    • one year ago
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    HI!!

  2. misty1212
    • one year ago
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    it is really \[\lim_{x\to 2}\frac{5}{(x-2)^2}\]?

  3. lynda.boyce
    • one year ago
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    yes

  4. misty1212
    • one year ago
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    then since the denominator goes to zero and the numerator does not, there is no limit

  5. welshfella
    • one year ago
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    Doesn't the deniminator approach zero but not gat there so the limit is infinity.?

  6. lynda.boyce
    • one year ago
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    thank you @misty1212

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