## lynda.boyce one year ago Ok, I'm not sure if I am doing this problem right. Let G(x)=5/(x-2)^2. Find the lim x 2 G(x). I used 2 in the equation. so I got G(x)=5/(2-2)^2. the answer comes up as undefined.

1. misty1212

HI!!

2. misty1212

it is really $\lim_{x\to 2}\frac{5}{(x-2)^2}$?

3. lynda.boyce

yes

4. misty1212

then since the denominator goes to zero and the numerator does not, there is no limit

5. welshfella

Doesn't the deniminator approach zero but not gat there so the limit is infinity.?

6. lynda.boyce

thank you @misty1212