lynda.boyce
  • lynda.boyce
Ok, I'm not sure if I am doing this problem right. Let G(x)=5/(x-2)^2. Find the lim x 2 G(x). I used 2 in the equation. so I got G(x)=5/(2-2)^2. the answer comes up as undefined.
Mathematics
katieb
  • katieb
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misty1212
  • misty1212
HI!!
misty1212
  • misty1212
it is really \[\lim_{x\to 2}\frac{5}{(x-2)^2}\]?
lynda.boyce
  • lynda.boyce
yes

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misty1212
  • misty1212
then since the denominator goes to zero and the numerator does not, there is no limit
welshfella
  • welshfella
Doesn't the deniminator approach zero but not gat there so the limit is infinity.?
lynda.boyce
  • lynda.boyce
thank you @misty1212

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