mathmath333
  • mathmath333
Find the area of the region enclosed .
Linear Algebra
katieb
  • katieb
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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mathmath333
  • mathmath333
\(\large \color{black}{\begin{align} |x+y|+|x-y|=8 \end{align}}\)
mathmath333
  • mathmath333
anonymous
  • anonymous
I'm the wrong person to ask. Everything I know about this topic came from following your questions.

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ParthKohli
  • ParthKohli
Hey, try graphing this.
ParthKohli
  • ParthKohli
It becomes a square with side length 8.
mathmath333
  • mathmath333
idk how to graph it with hand
ParthKohli
  • ParthKohli
You get four lines:\[+(x+y) + (x-y) = 8\tag{1}\]\[+(x+y) - (x-y) = 8\tag 2 \]\[-(x+y) +(x-y) = 8\tag 3 \]\[-(x+y) - (x-y) = 8 \tag 4 \]
ParthKohli
  • ParthKohli
Of course the graph for these four lines and \(|x+y| + |x-y| = 8\) is not identical, but both of them still make a square.
mathmath333
  • mathmath333
thnx!
mathmath333
  • mathmath333

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