Jravenv
  • Jravenv
Help me, Best answer rewarded, screencap in comments.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Jravenv
  • Jravenv
Astrophysics
  • Astrophysics
Start off by cross multiplying
Astrophysics
  • Astrophysics
\[(k+1)(9) = 4(2k-3)\] distribute collect like terms...etc.

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More answers

Jravenv
  • Jravenv
Can you tell me how to do that?
Astrophysics
  • Astrophysics
|dw:1434142179368:dw| you should be able to finish it off now
Astrophysics
  • Astrophysics
Yay for direct answers and not learning!
anonymous
  • anonymous
Oh sorry..
Jravenv
  • Jravenv
What? theres no direct answer?
Astrophysics
  • Astrophysics
Anyways..did you get the answer?
Jravenv
  • Jravenv
-3 right?
Astrophysics
  • Astrophysics
No, how did you get that?
Astrophysics
  • Astrophysics
\[9k+9 = 8k-12\] collect like terms
Jravenv
  • Jravenv
I'm lost already,
Astrophysics
  • Astrophysics
Ok, lets start from the begining then
Astrophysics
  • Astrophysics
Or if you can tell me specifically where you are lost
Jravenv
  • Jravenv
Would I be getting 17k and -3
Astrophysics
  • Astrophysics
|dw:1434142812377:dw|
Astrophysics
  • Astrophysics
What do we get now
Jravenv
  • Jravenv
1k=-21
Astrophysics
  • Astrophysics
Yes :)
Astrophysics
  • Astrophysics
1k is the same thing as just k, so our answer will be k = -21
anonymous
  • anonymous
I knew it !
Jravenv
  • Jravenv
Thank y'all!
anonymous
  • anonymous
You are welcome!
Astrophysics
  • Astrophysics
Haha good job @mathman101 and your welcome
anonymous
  • anonymous
Thanks

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