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Jravenv
 one year ago
Help me,
Best answer rewarded,
screencap in comments.
Jravenv
 one year ago
Help me, Best answer rewarded, screencap in comments.

This Question is Closed

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Start off by cross multiplying

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[(k+1)(9) = 4(2k3)\] distribute collect like terms...etc.

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.2Can you tell me how to do that?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434142179368:dw you should be able to finish it off now

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Yay for direct answers and not learning!

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.2What? theres no direct answer?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Anyways..did you get the answer?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2No, how did you get that?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2\[9k+9 = 8k12\] collect like terms

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Ok, lets start from the begining then

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Or if you can tell me specifically where you are lost

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.2Would I be getting 17k and 3

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2dw:1434142812377:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2What do we get now

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.21k is the same thing as just k, so our answer will be k = 21

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.2Haha good job @mathman101 and your welcome
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