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faf3
 one year ago
x^2 +y^2+4x2y20
I have to graph this circle, but how do i find the midpoint?
faf3
 one year ago
x^2 +y^2+4x2y20 I have to graph this circle, but how do i find the midpoint?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That entire thing is one equation?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The only way it can be a circle equation is if it's in the form of Ax^2 + By^2 = C

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What's the exact question?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1At least it must be an equation with an equal sign and something on the right side of the equal sign.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to complete the square? if so, here do it twice: from \(x^2 +y^2+4x2y20\), do it for the \(x^2 +4x\) and \(y^22y\) parts and keep a close eye on the remaining numbers you can the do the graph in one go using a compass
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