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faf3

  • one year ago

x^2 +y^2+4x-2y-20 I have to graph this circle, but how do i find the midpoint?

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  1. anonymous
    • one year ago
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    That entire thing is one equation?

  2. anonymous
    • one year ago
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    The only way it can be a circle equation is if it's in the form of Ax^2 + By^2 = C

  3. anonymous
    • one year ago
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    What's the exact question?

  4. mathstudent55
    • one year ago
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    At least it must be an equation with an equal sign and something on the right side of the equal sign.

  5. IrishBoy123
    • one year ago
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    do you know how to complete the square? if so, here do it twice: from \(x^2 +y^2+4x-2y-20\), do it for the \(x^2 +4x\) and \(y^2-2y\) parts and keep a close eye on the remaining numbers you can the do the graph in one go using a compass

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