## lizz123 one year ago @Nnesha Simplify each expression. http://prntscr.com/7gaed3

1. lizz123

|dw:1434148381810:dw|

2. Nnesha
3. lizz123

|dw:1434148529534:dw|

4. Nnesha

mhm remember distribute last parentheses by negative one $\large\rm \color{red}{-1}(x^4y^3+x^4y^4)=\color{red}{-1}(x^4y^3) ) \color{reD}{-1} (x^4y^4)$

5. Nnesha

|dw:1434148785729:dw| it's 6y to the 3rd power you forgot 3 :-)

6. Nnesha

|dw:1434148834370:dw|

7. lizz123

|dw:1434148834313:dw|

8. Nnesha

distribute last parentheses|dw:1434149272563:dw| by negative one

9. Nnesha

i made a type let me fixx that

10. Nnesha

$$\color{blue}{\text{Originally Posted by}}$$ @Nnesha mhm remember distribute last parentheses by negative one $\large\rm \color{red}{-1}(x^4y^3+x^4y^4)=\color{red}{-1}(x^4y^3) ) \color{reD}{-1} (x^4y^4)$ $$\color{blue}{\text{End of Quote}}$$ supposed to be $\large\rm \color{red}{-1}(x^4y^3+6x^4y^4)=\color{red}{-1}(x^4y^3) ) \color{reD}{-1} (6x^4y^4)$ now distribute -1 times 6x^4y^4 = -6x^4y^4 right negative times positive = negative

11. lizz123

so would the answer be $7x ^{3}-9x ^{4}y ^{4}-11x ^{4 }y ^{3}$

12. Nnesha

yep! :-)