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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1mhm remember distribute last parentheses by negative one \[\large\rm \color{red}{1}(x^4y^3+x^4y^4)=\color{red}{1}(x^4y^3) ) \color{reD}{1} (x^4y^4)\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434148785729:dw it's 6y to the 3rd power you forgot 3 :)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1distribute last parenthesesdw:1434149272563:dw by negative one

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1i made a type let me fixx that

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @Nnesha mhm remember distribute last parentheses by negative one \[\large\rm \color{red}{1}(x^4y^3+x^4y^4)=\color{red}{1}(x^4y^3) ) \color{reD}{1} (x^4y^4)\] \(\color{blue}{\text{End of Quote}}\) supposed to be \[\large\rm \color{red}{1}(x^4y^3+6x^4y^4)=\color{red}{1}(x^4y^3) ) \color{reD}{1} (6x^4y^4)\] now distribute 1 times 6x^4y^4 = 6x^4y^4 right negative times positive = negative

lizz123
 one year ago
Best ResponseYou've already chosen the best response.1so would the answer be \[7x ^{3}9x ^{4}y ^{4}11x ^{4 }y ^{3}\]
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