lizz123
  • lizz123
@Nnesha Simplify each expression. http://prntscr.com/7gaed3
Mathematics
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SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
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lizz123
  • lizz123
|dw:1434148381810:dw|
Nnesha
  • Nnesha
sign http://prntscr.com/7gafxl
lizz123
  • lizz123
|dw:1434148529534:dw|

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Nnesha
  • Nnesha
mhm remember distribute last parentheses by negative one \[\large\rm \color{red}{-1}(x^4y^3+x^4y^4)=\color{red}{-1}(x^4y^3) ) \color{reD}{-1} (x^4y^4)\]
Nnesha
  • Nnesha
|dw:1434148785729:dw| it's 6y to the 3rd power you forgot 3 :-)
Nnesha
  • Nnesha
|dw:1434148834370:dw|
lizz123
  • lizz123
|dw:1434148834313:dw|
Nnesha
  • Nnesha
distribute last parentheses|dw:1434149272563:dw| by negative one
Nnesha
  • Nnesha
i made a type let me fixx that
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha mhm remember distribute last parentheses by negative one \[\large\rm \color{red}{-1}(x^4y^3+x^4y^4)=\color{red}{-1}(x^4y^3) ) \color{reD}{-1} (x^4y^4)\] \(\color{blue}{\text{End of Quote}}\) supposed to be \[\large\rm \color{red}{-1}(x^4y^3+6x^4y^4)=\color{red}{-1}(x^4y^3) ) \color{reD}{-1} (6x^4y^4)\] now distribute -1 times 6x^4y^4 = -6x^4y^4 right negative times positive = negative
lizz123
  • lizz123
so would the answer be \[7x ^{3}-9x ^{4}y ^{4}-11x ^{4 }y ^{3}\]
Nnesha
  • Nnesha
yep! :-)

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