anonymous
  • anonymous
Simplify: (21x^3y^4) / (-7xy) A. -3x^2y^3 B. -3xy C. 14x^2y^3 D. 14xy My answer: A PLease show me how to get the answer my teacher is a told brat.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@pooja195
pooja195
  • pooja195
@Nnesha
anonymous
  • anonymous
@Awolflover1 @zepdrix

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Nnesha
  • Nnesha
\[\huge\rm \frac{ x^m }{ x^n } = x^{m-n}\] move exponent from bottom to the top of fraction (if bases are the same )
Nnesha
  • Nnesha
\[\large\rm \frac{21x^3y^4}{ -7xy} = -\frac{ 21 }{ 7 } \times \frac{ x^3 }{ x } \times \frac{ y^4 }{ y }\]
anonymous
  • anonymous
that not right the / spouse to mean divid
Nnesha
  • Nnesha
yeah ik
Nnesha
  • Nnesha
what's not correct ??
anonymous
  • anonymous
nothing I though you though that was a fraction
Nnesha
  • Nnesha
yep that's a fraction :-)
Nnesha
  • Nnesha
or you can factor x^3 remember exponent rule when you multiply same bases you should add their exponents \[\huge\rm x^m \times x^n = x^{m+n}\] so you can write \[\large\rm x^3 = x \times x \times x \]
Nnesha
  • Nnesha
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\large\rm \frac{21x^3y^4}{ -7xy} = -\frac{ 21 }{ 7 } \times \frac{ x^3 }{ x } \times \frac{ y^4 }{ y }\] \(\color{blue}{\text{End of Quote}}\) \[\large\rm -\frac{ 21 }{ 7 } \times \frac{ x \times x \times x }{ x } \times \frac{ y^4 }{ y }\] now cancel ot x
anonymous
  • anonymous
so their is only 2 x left
Nnesha
  • Nnesha
^^yep x times x can be written as = ??? hint exponent rule x^m times x^n = x^{m+n}
anonymous
  • anonymous
okay thanks
Nnesha
  • Nnesha
got it ??
Nnesha
  • Nnesha
so what's ur answer ??
anonymous
  • anonymous
oops sorry -3x^2y^3

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