Simplify: (21x^3y^4) / (-7xy) A. -3x^2y^3 B. -3xy C. 14x^2y^3 D. 14xy My answer: A PLease show me how to get the answer my teacher is a told brat.

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Simplify: (21x^3y^4) / (-7xy) A. -3x^2y^3 B. -3xy C. 14x^2y^3 D. 14xy My answer: A PLease show me how to get the answer my teacher is a told brat.

Mathematics
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\[\huge\rm \frac{ x^m }{ x^n } = x^{m-n}\] move exponent from bottom to the top of fraction (if bases are the same )
\[\large\rm \frac{21x^3y^4}{ -7xy} = -\frac{ 21 }{ 7 } \times \frac{ x^3 }{ x } \times \frac{ y^4 }{ y }\]
that not right the / spouse to mean divid
yeah ik
what's not correct ??
nothing I though you though that was a fraction
yep that's a fraction :-)
or you can factor x^3 remember exponent rule when you multiply same bases you should add their exponents \[\huge\rm x^m \times x^n = x^{m+n}\] so you can write \[\large\rm x^3 = x \times x \times x \]
\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\large\rm \frac{21x^3y^4}{ -7xy} = -\frac{ 21 }{ 7 } \times \frac{ x^3 }{ x } \times \frac{ y^4 }{ y }\] \(\color{blue}{\text{End of Quote}}\) \[\large\rm -\frac{ 21 }{ 7 } \times \frac{ x \times x \times x }{ x } \times \frac{ y^4 }{ y }\] now cancel ot x
so their is only 2 x left
^^yep x times x can be written as = ??? hint exponent rule x^m times x^n = x^{m+n}
okay thanks
got it ??
so what's ur answer ??
oops sorry -3x^2y^3

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