i give medals g(x) = x2 +6x + 1 solve

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i give medals g(x) = x2 +6x + 1 solve

Mathematics
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in quadratic formula
thanks
\[x=-3\pm 2 \sqrt{2} \]

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Other answers:

and what are the steps
what are you solving for?
help plz
g(x) = x2 +6x + 1
but what do we solve?
are you trying to solve g(x)=0 for x?
are you trying ting solve g(x)=1 ?
in quadratic formula
so on...
i know robertobey is the right answer i just need the steps
can you help me on that
so are you solving x^2+6x+1=0 ?
yup
ok I didn't see this equation anywhere when you said solve so you can understand my confusion on what we want to solve
yes
anyways first compare x^2+6x+1=0 to ax^2+bx+c=0 identify a,b, and c?
okay so i dont know what to do after x= -6 plus and minus root 32 all over 2
|dw:1434157255670:dw|
\[\text{ quadratic formula is } \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \text{ replace } a \text{ with } 1 \\ \text{ replace } b \text{ with 6} \\ \text{ replace } c \text{ with 1} \\ x=\frac{-6 \pm \sqrt{6^2-4(1)(1)}}{2(1)} \\ x=\frac{-6 \pm \sqrt{36-4}}{2} \\ x=\frac{-6 \pm \sqrt{32}}{2} \\ \text{ hint to continue } \sqrt{32}=\sqrt{16 \cdot 2} =\sqrt{16} \cdot \sqrt{2}=4 \sqrt{2}\]
umm okay then you divide the 4 into 2
\[x=\frac{-6 \pm 4 \sqrt{2}}{2} \\ x=\frac{-6}{2} \pm \frac{4 \sqrt{2}}{2} \\ x=\frac{-6}{2} \pm \frac{4}{2} \sqrt{2}\]
Ohhhhhh okay thank you so much
np
and you can simplify the -6/2 part and the 4/2 part and get what that one guy got
anyways peace :)

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