## itsmichelle29 one year ago i give medals g(x) = x2 +6x + 1 solve

1. itsmichelle29

2. itsmichelle29

thanks

3. anonymous

$x=-3\pm 2 \sqrt{2}$

4. itsmichelle29

and what are the steps

5. freckles

what are you solving for?

6. itsmichelle29

help plz

7. itsmichelle29

g(x) = x2 +6x + 1

8. freckles

but what do we solve?

9. freckles

are you trying to solve g(x)=0 for x?

10. freckles

are you trying ting solve g(x)=1 ?

11. itsmichelle29

12. freckles

so on...

13. itsmichelle29

i know robertobey is the right answer i just need the steps

14. itsmichelle29

can you help me on that

15. freckles

so are you solving x^2+6x+1=0 ?

16. itsmichelle29

yup

17. freckles

ok I didn't see this equation anywhere when you said solve so you can understand my confusion on what we want to solve

18. itsmichelle29

yes

19. freckles

anyways first compare x^2+6x+1=0 to ax^2+bx+c=0 identify a,b, and c?

20. itsmichelle29

okay so i dont know what to do after x= -6 plus and minus root 32 all over 2

21. itsmichelle29

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22. freckles

$\text{ quadratic formula is } \\ x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \text{ replace } a \text{ with } 1 \\ \text{ replace } b \text{ with 6} \\ \text{ replace } c \text{ with 1} \\ x=\frac{-6 \pm \sqrt{6^2-4(1)(1)}}{2(1)} \\ x=\frac{-6 \pm \sqrt{36-4}}{2} \\ x=\frac{-6 \pm \sqrt{32}}{2} \\ \text{ hint to continue } \sqrt{32}=\sqrt{16 \cdot 2} =\sqrt{16} \cdot \sqrt{2}=4 \sqrt{2}$

23. itsmichelle29

umm okay then you divide the 4 into 2

24. freckles

$x=\frac{-6 \pm 4 \sqrt{2}}{2} \\ x=\frac{-6}{2} \pm \frac{4 \sqrt{2}}{2} \\ x=\frac{-6}{2} \pm \frac{4}{2} \sqrt{2}$

25. itsmichelle29

Ohhhhhh okay thank you so much

26. freckles

np

27. freckles

and you can simplify the -6/2 part and the 4/2 part and get what that one guy got

28. freckles

anyways peace :)