anonymous
  • anonymous
A radioactive isotope has a half-life of one week. How much of it will remain after one month? Show all calculations leading to an answer OR explain your answer with 3 – 4 complete sentences.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
@hugekabab
anonymous
  • anonymous
ooo half life ... its been a while since i did these ... let me think
anonymous
  • anonymous
ok

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anonymous
  • anonymous
ok listen closely
anonymous
  • anonymous
assume that the isotope starts at x units
anonymous
  • anonymous
. after 1 week half will be gone, or x/2, after the second week half of what remains will be gone. x/2 /2 or x/4, after three weeks x/8 and after 4 weeks, x/16 or 1/16 of the starting amount
anonymous
  • anonymous
get it ?
anonymous
  • anonymous
yes i kinda already understood half life basically each weach this isotope will loose half of it total life left
anonymous
  • anonymous
yup
anonymous
  • anonymous
btw i gotta ask ... is this for hig school ?
anonymous
  • anonymous
so W1=1/2 W4=1/16
anonymous
  • anonymous
so at 1 month it will have 1/16 of its life
anonymous
  • anonymous
thats what i think
anonymous
  • anonymous
ok thank you
anonymous
  • anonymous
half of the orignal in the first week ... half of the half left in the second week (quater of the orignal) and so on
anonymous
  • anonymous
get the sequence ?
anonymous
  • anonymous
and just to clarify on the last question we did i divided those numbers and got 60041537135.7 and i add KG-J
anonymous
  • anonymous
yes i got it thank you so much
anonymous
  • anonymous
just kg .... cause its just simple mass ... nothing more ..and btw ... do the math again just to be sure yu have the figures right ..
anonymous
  • anonymous
i was kinda hoping for a medal ...its like my first time here on open study ... and damn is this place cool
anonymous
  • anonymous
i literally divided the two as is
anonymous
  • anonymous
yeah yu did multiply it by C right ? the speed of light
anonymous
  • anonymous
yu did right ... as long as you multiplied C as well
anonymous
  • anonymous
no i divided m=e/c^2
anonymous
  • anonymous
yeah divide ...sorry my bad
anonymous
  • anonymous
its correct thrn
anonymous
  • anonymous
then *
anonymous
  • anonymous
C must be in m/s
anonymous
  • anonymous
and what about the ^2 over c? is that encompassed in the number i used for the speed of light
anonymous
  • anonymous
yes .. thats the speed of light squared
anonymous
  • anonymous
ok
anonymous
  • anonymous
well thank you than
anonymous
  • anonymous
no problem ... always happy to help ..

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