A radioactive isotope has a half-life of one week. How much of it will remain after one month? Show all calculations leading to an answer OR explain your answer with 3 – 4 complete sentences.

- anonymous

- schrodinger

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- anonymous

- anonymous

ooo half life ... its been a while since i did these ... let me think

- anonymous

ok

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## More answers

- anonymous

ok listen closely

- anonymous

assume that the isotope starts at x units

- anonymous

. after 1 week half will be gone, or x/2, after the second week half of what remains will be gone. x/2 /2 or x/4, after three weeks x/8 and after 4 weeks, x/16 or 1/16 of the starting amount

- anonymous

get it ?

- anonymous

yes i kinda already understood half life basically each weach this isotope will loose half of it total life left

- anonymous

yup

- anonymous

btw i gotta ask ... is this for hig school ?

- anonymous

so
W1=1/2
W4=1/16

- anonymous

so at 1 month it will have 1/16 of its life

- anonymous

thats what i think

- anonymous

ok thank you

- anonymous

half of the orignal in the first week ... half of the half left in the second week (quater of the orignal) and so on

- anonymous

get the sequence ?

- anonymous

and just to clarify on the last question we did i divided those numbers and got 60041537135.7 and i add KG-J

- anonymous

yes i got it thank you so much

- anonymous

just kg .... cause its just simple mass ... nothing more ..and btw ... do the math again just to be sure yu have the figures right ..

- anonymous

i was kinda hoping for a medal ...its like my first time here on open study ... and damn is this place cool

- anonymous

i literally divided the two as is

- anonymous

yeah yu did multiply it by C right ? the speed of light

- anonymous

yu did right ... as long as you multiplied C as well

- anonymous

no i divided
m=e/c^2

- anonymous

yeah divide ...sorry my bad

- anonymous

its correct thrn

- anonymous

then *

- anonymous

C must be in m/s

- anonymous

and what about the ^2 over c? is that encompassed in the number i used for the speed of light

- anonymous

yes .. thats the speed of light squared

- anonymous

ok

- anonymous

well thank you than

- anonymous

no problem ... always happy to help ..

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