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Jravenv
 one year ago
Help please
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Jravenv
 one year ago
Help please best answer rewarded screencap in comments

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ybarrap
 one year ago
Best ResponseYou've already chosen the best response.1Break this up into pieces Can you factor \(m^24\)?

Jravenv
 one year ago
Best ResponseYou've already chosen the best response.0Nope I have no idea how to do any of this

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.1$$ (m+2)(m2)=m^22m+2m4=m^24 $$ Do you see that?

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0we can factor out like terms and then cancel anything that's the same in the numerator and the denominator.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{3m6}{4m+12}\] let's consider this part of the problem... there is a number in common on 3m 6. What number can I factor out? also what is 3/3 and 6/3 similarly what number can I factor out? what is 4/4 and 12/4 for the denominator..

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I can pull out a 3 for 3m6 and I will have 3(m2). I can pull out a 4 for 4m+12 and I will have 4(m+3)

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{m^2+5m+6}{m^24}\] this requires factoring as well. We have a perfect square on the bottom of the denominator. now we just need to factor the numerator which is \[m^2+5m+6\] We need to focus on all combinations that make 6 and use addition or subtraction to make a 5 the combinations of 6 are 6 and 1 1 and 6 2 and 3 3 and 2

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.06 and 1 isn't going to work . If I add them together it's 7... subtract and it's a 5. Well why can't we use this? Because our equation has double + signs... so it requires all numbers to be positive.

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.02 and 3 will work just fine. Not only is it 2 x 3 = 6, but 2+3 =5 so our \[m^2+5m+6 \rightarrow (m+2)(m+3)\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{3(m2)}{4(m+3)} \times \frac{(m+2)(m+3)}{(m+2)(m2)}\]

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0there are a bunch of terms to cancel out I see (m+3) on the numerator and denominator...the same case happens for (m2) and (m+2). ANd then you are left with \[\frac{3}{4}\]
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