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anonymous
 one year ago
(4a4 − 27a3 + 53a2 − 42a + 24) ÷ (a2 − 6a + 8)
anonymous
 one year ago
(4a4 − 27a3 + 53a2 − 42a + 24) ÷ (a2 − 6a + 8)

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shamim
 one year ago
Best ResponseYou've already chosen the best response.2Agsin factorise 4a^427a^3+53a^242a+24

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(4a^2  3a + 3) (a  2) (a  4)

shamim
 one year ago
Best ResponseYou've already chosen the best response.2Now just cancell out frm numerator n denominator

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would be 4a^23a+3 ?

shamim
 one year ago
Best ResponseYou've already chosen the best response.2Wt u will get after cancellation

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0I am wondering if this problem is really just use factoring to cancel out like terms. Or solve this equation using long division.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I haven't tried to solve it myself, but if the numerator can be factored nicely, it would yield the same result. I have to leave shortly but I can try and work through it before I do

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@UsukiDoll I got the same answer by long division. @shamim 's method seems absolutely fine to me

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.0ok...it's probably because I wasn't taught that method which I wondered why that was valid.
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