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anonymous

  • one year ago

(4a4 − 27a3 + 53a2 − 42a + 24) ÷ (a2 − 6a + 8)

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  1. shamim
    • one year ago
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    Plz factorise a^2-6a+8

  2. shamim
    • one year ago
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    Agsin factorise 4a^4-27a^3+53a^2-42a+24

  3. anonymous
    • one year ago
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    (a-4)(a-2)

  4. shamim
    • one year ago
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    Right

  5. anonymous
    • one year ago
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    (4a^2 - 3a + 3) (a - 2) (a - 4)

  6. shamim
    • one year ago
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    Now just cancell out frm numerator n denominator

  7. anonymous
    • one year ago
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    so the answer would be 4a^2-3a+3 ?

  8. shamim
    • one year ago
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    Wt u will get after cancellation

  9. shamim
    • one year ago
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    Correct!!!!

  10. anonymous
    • one year ago
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    Thanks!!

  11. shamim
    • one year ago
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    U r most welcome!!

  12. UsukiDoll
    • one year ago
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    I am wondering if this problem is really just use factoring to cancel out like terms. Or solve this equation using long division.

  13. anonymous
    • one year ago
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    I haven't tried to solve it myself, but if the numerator can be factored nicely, it would yield the same result. I have to leave shortly but I can try and work through it before I do

  14. anonymous
    • one year ago
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    @UsukiDoll I got the same answer by long division. @shamim 's method seems absolutely fine to me

  15. UsukiDoll
    • one year ago
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    ok...it's probably because I wasn't taught that method which I wondered why that was valid.

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