Velocity Question

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Velocity Question

Mathematics
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The world record for fresh hen’s egg throwing is 96.90 m, set in 1981. Assuming no air resistance, what would have been the (a) throwing speed; (b) elevation angle; (c) maximum height; (d) time of flight?
I'm having some weird issues, where I am given too little information to solve...
Let \(x\) be the total velocity \(x_h=x\times\cos\left(\theta\right)\) \(x_y=x\times\sin\left(\theta\right)\) \[t=\frac{96.90}{x\times\cos\left(\theta\right)}\] \[s_y=x_yt+\frac{1}{2}a_yt^2\] \[0=x\times\cos\left(\theta\right)\times\left(\frac{96.90}{x\times\cos\left(\theta\right)}\right)+\frac{1}{2}\times-9.8\times\left(\frac{96.90}{x\times\cos\left(\theta\right)}\right)^2\]

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Other answers:

If the world record is set then the angle of elevation should be 45 degrees otherwise it would not have been a record
Then why would they ask for elevation angle..?
Whoops, thats meant to be \(x\times \sin\left(\theta\right)\)
For \(x_y\)
i also think it is justified to use 45° as the elevation angle
But I still don't know why they would ask it in the question... let me look at the solution
Wow. The angle is 45 degrees in the book -_-
Can you solve it without knowing the angle?
its like common sense @Ahsome :P
you cannot use common sense in physics
But I guess I'll just assume you had to assume the whole time..?
any other ideas?? @nincompoop
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90 degrees would most likely not reach the distance horizontally
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For a given range, the max height could be "anything", so there is no unique answer. To get an unique answer we need to use a bit of common sense here that the given range is the world record (maximum possible for a given velocity)
thankyou @ganeshie8
The answer itself says the angle is 45 degrees
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45 degree angle is the optimal angle provided the same newton force is applied
as the egg elevates gravity is pushing it down
Then why would part of the question ask what is the angle...
http://www.schoolphysics.co.uk/age16-19/Mechanics/Kinematics/text/Projectiles_projection_at_an_angle/index.html
They are testing if you know that the maximum is achieved when \(\theta = 45\) you may prove it if you want to..
*maximum range
You need to assume the starting speed is constant (all humans have more or less same throwing power) and vary only the angle and see which angle produces maximum range
correct, and that is determined by the velocity of the egg itself
\[R = \dfrac{v_0^2\sin(2\theta)}{g}\] what angle makes \(R\) large ?
45 degrees? Since \(45\times 2=90\) and \(sin(90)=1\)
Yep! maybe just put that for justification
correct
Ahh, thanks @ganeshie8 and @nincompoop and everybody who helped :D
np:) please medal divu.mkr not me
If you say so @ganeshie8 ;)

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