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Ahsome

  • one year ago

Velocity Question

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  1. ahsome
    • one year ago
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    The world record for fresh hen’s egg throwing is 96.90 m, set in 1981. Assuming no air resistance, what would have been the (a) throwing speed; (b) elevation angle; (c) maximum height; (d) time of flight?

  2. ahsome
    • one year ago
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    I'm having some weird issues, where I am given too little information to solve...

  3. ahsome
    • one year ago
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    Let \(x\) be the total velocity \(x_h=x\times\cos\left(\theta\right)\) \(x_y=x\times\sin\left(\theta\right)\) \[t=\frac{96.90}{x\times\cos\left(\theta\right)}\] \[s_y=x_yt+\frac{1}{2}a_yt^2\] \[0=x\times\cos\left(\theta\right)\times\left(\frac{96.90}{x\times\cos\left(\theta\right)}\right)+\frac{1}{2}\times-9.8\times\left(\frac{96.90}{x\times\cos\left(\theta\right)}\right)^2\]

  4. anonymous
    • one year ago
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    If the world record is set then the angle of elevation should be 45 degrees otherwise it would not have been a record

  5. ahsome
    • one year ago
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    Then why would they ask for elevation angle..?

  6. ahsome
    • one year ago
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    Whoops, thats meant to be \(x\times \sin\left(\theta\right)\)

  7. ahsome
    • one year ago
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    For \(x_y\)

  8. ahsome
    • one year ago
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    Any dieas @ganeshie8 @UnkleRhaukus ?

  9. UnkleRhaukus
    • one year ago
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    i also think it is justified to use 45° as the elevation angle

  10. ahsome
    • one year ago
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    But I still don't know why they would ask it in the question... let me look at the solution

  11. ahsome
    • one year ago
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    Wow. The angle is 45 degrees in the book -_-

  12. ahsome
    • one year ago
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    Can you solve it without knowing the angle?

  13. anonymous
    • one year ago
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    its like common sense @Ahsome :P

  14. nincompoop
    • one year ago
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    you cannot use common sense in physics

  15. ahsome
    • one year ago
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    @nincompoop, TRUTH

  16. ahsome
    • one year ago
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    But I guess I'll just assume you had to assume the whole time..?

  17. anonymous
    • one year ago
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    any other ideas?? @nincompoop

  18. ganeshie8
    • one year ago
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    |dw:1434178782194:dw|

  19. nincompoop
    • one year ago
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    |dw:1434178667144:dw|

  20. nincompoop
    • one year ago
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    90 degrees would most likely not reach the distance horizontally

  21. nincompoop
    • one year ago
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    |dw:1434178899967:dw|

  22. ganeshie8
    • one year ago
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    For a given range, the max height could be "anything", so there is no unique answer. To get an unique answer we need to use a bit of common sense here that the given range is the world record (maximum possible for a given velocity)

  23. anonymous
    • one year ago
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    thankyou @ganeshie8

  24. ahsome
    • one year ago
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    The answer itself says the angle is 45 degrees

  25. nincompoop
    • one year ago
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    |dw:1434178985932:dw|

  26. nincompoop
    • one year ago
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    45 degree angle is the optimal angle provided the same newton force is applied

  27. nincompoop
    • one year ago
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    as the egg elevates gravity is pushing it down

  28. ahsome
    • one year ago
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    Then why would part of the question ask what is the angle...

  29. ganeshie8
    • one year ago
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    They are testing if you know that the maximum is achieved when \(\theta = 45\) you may prove it if you want to..

  30. ganeshie8
    • one year ago
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    *maximum range

  31. ganeshie8
    • one year ago
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    You need to assume the starting speed is constant (all humans have more or less same throwing power) and vary only the angle and see which angle produces maximum range

  32. nincompoop
    • one year ago
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    correct, and that is determined by the velocity of the egg itself

  33. ganeshie8
    • one year ago
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    \[R = \dfrac{v_0^2\sin(2\theta)}{g}\] what angle makes \(R\) large ?

  34. ahsome
    • one year ago
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    45 degrees? Since \(45\times 2=90\) and \(sin(90)=1\)

  35. ganeshie8
    • one year ago
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    Yep! maybe just put that for justification

  36. nincompoop
    • one year ago
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    correct

  37. ahsome
    • one year ago
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    Ahh, thanks @ganeshie8 and @nincompoop and everybody who helped :D

  38. ganeshie8
    • one year ago
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    np:) please medal divu.mkr not me

  39. ahsome
    • one year ago
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    If you say so @ganeshie8 ;)

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