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anonymous
 one year ago
A particular circle in the standard (x,y) coordinate plane has an equation of (x5) squared + y squared = 38. What are the radius of the circle, in coordinate units, and the coordinates of the center of the circle?
anonymous
 one year ago
A particular circle in the standard (x,y) coordinate plane has an equation of (x5) squared + y squared = 38. What are the radius of the circle, in coordinate units, and the coordinates of the center of the circle?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The coordinates of the centre are (1,0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Could you give me an explanation of how you got your answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Also the + was actually supposed to be an = so excuse that my bad

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0expand the equation given to get \[x ^{2}+y ^{2}2x +63 = 0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0general equation of a circle is x^2 + Y^2 +2gx + 2fy + c = 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The equation is \[(x5)^{2}+y ^{2}=38\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Comparing the two we get g = 1 y=0 Also centre is equal to (g.f)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sorry the centre would be (1,0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think the center would be 5,0 because if we set x to =0 we get x=5 and since the y is only squared the y would automatically be 0. I just can't remember the radius. All i know is that it's the number the whole thing is equal to and i think it's square rooted.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks though! I think i've got the answer :)
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