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Ehsan18

  • one year ago

Q75. Water flowing through a tube having variable cross-sectional area is shown in the figure below.

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  1. Ehsan18
    • one year ago
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  2. Ehsan18
    • one year ago
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    @perl

  3. perl
    • one year ago
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    I believe it is all tubes

  4. Ehsan18
    • one year ago
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    Yeah I think the same, but can you back it up?

  5. perl
    • one year ago
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    We might be able to apply Bernoulli's principle

  6. Ehsan18
    • one year ago
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    Could you please apply it and tell me how it looks like..

  7. perl
    • one year ago
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    I am reading this. http://physics.stackexchange.com/questions/799/why-does-the-water-level-equalize-in-a-series-of-tubes It has something to do with the pressure being constant

  8. perl
    • one year ago
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    That article deals with static water, it might be different when you have flowing water

  9. Ehsan18
    • one year ago
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    It is, because when the water is static, it has a property to maintain a certain level, its used in hydraulics too...but when it comes to flowing liquid its Bernoulli equation

  10. perl
    • one year ago
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    Can we assume the tubes are open to the atmosphere

  11. Ehsan18
    • one year ago
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    yes maybe, I think its tube 3 according to eq. of continuity A1v1=A2v2 A=area. v=velocity

  12. Ehsan18
    • one year ago
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    is it all the tubes?

  13. Ehsan18
    • one year ago
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    @Astrophysics @ikram002p

  14. Ehsan18
    • one year ago
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    @nincompoop

  15. sohailiftikhar
    • one year ago
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    its tube III because here speed is slow than other and hence pressure is high due to which goes up to its maximum level ....

  16. sohailiftikhar
    • one year ago
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    ????

  17. sohailiftikhar
    • one year ago
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    are you there ????

  18. Ehsan18
    • one year ago
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    @Michele_Laino

  19. Michele_Laino
    • one year ago
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    If the motion of water is uniform, then we can apply the continuity equation: \[Av = {\text{constant}}\] so we can write: \[{A_1}{v_1} = {A_2}{v_2} = {A_3}{v_3}\]

  20. Michele_Laino
    • one year ago
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    where A is the cross sectional area of the tube

  21. Michele_Laino
    • one year ago
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    so we have the minimum value of the speed at section #3

  22. Michele_Laino
    • one year ago
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    next we have to consider the Theorem of Bernoulli: \[z + \frac{P}{\gamma } + \frac{{{v^2}}}{{2g}} = const\] where P is the pressure, and \gamma is the specific weight of the water

  23. Michele_Laino
    • one year ago
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    so the pressure P is maximum at the section where the speed v is minimum. What can you conclude?

  24. Michele_Laino
    • one year ago
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    more precisely, the quantity: \[\frac{P}{\gamma }\] is called the "groundwater level"

  25. Ehsan18
    • one year ago
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    We don't know anything about speed, probably depends upon the Area so its tube 3 most probably...what is your final answer?

  26. Michele_Laino
    • one year ago
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    yes! at the tube #3 the pressure is the highest and so it is the level reached by water

  27. Ehsan18
    • one year ago
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    Thanks guess I can close it now.

  28. Michele_Laino
    • one year ago
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    :)

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