A community for students.
Here's the question you clicked on:
 0 viewing
Ehsan18
 one year ago
Q75. Water flowing through a tube having variable crosssectional area is shown
in the figure below.
Ehsan18
 one year ago
Q75. Water flowing through a tube having variable crosssectional area is shown in the figure below.

This Question is Closed

perl
 one year ago
Best ResponseYou've already chosen the best response.0I believe it is all tubes

Ehsan18
 one year ago
Best ResponseYou've already chosen the best response.0Yeah I think the same, but can you back it up?

perl
 one year ago
Best ResponseYou've already chosen the best response.0We might be able to apply Bernoulli's principle

Ehsan18
 one year ago
Best ResponseYou've already chosen the best response.0Could you please apply it and tell me how it looks like..

perl
 one year ago
Best ResponseYou've already chosen the best response.0I am reading this. http://physics.stackexchange.com/questions/799/whydoesthewaterlevelequalizeinaseriesoftubes It has something to do with the pressure being constant

perl
 one year ago
Best ResponseYou've already chosen the best response.0That article deals with static water, it might be different when you have flowing water

Ehsan18
 one year ago
Best ResponseYou've already chosen the best response.0It is, because when the water is static, it has a property to maintain a certain level, its used in hydraulics too...but when it comes to flowing liquid its Bernoulli equation

perl
 one year ago
Best ResponseYou've already chosen the best response.0Can we assume the tubes are open to the atmosphere

Ehsan18
 one year ago
Best ResponseYou've already chosen the best response.0yes maybe, I think its tube 3 according to eq. of continuity A1v1=A2v2 A=area. v=velocity

Ehsan18
 one year ago
Best ResponseYou've already chosen the best response.0@Astrophysics @ikram002p

sohailiftikhar
 one year ago
Best ResponseYou've already chosen the best response.0its tube III because here speed is slow than other and hence pressure is high due to which goes up to its maximum level ....

sohailiftikhar
 one year ago
Best ResponseYou've already chosen the best response.0are you there ????

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1If the motion of water is uniform, then we can apply the continuity equation: \[Av = {\text{constant}}\] so we can write: \[{A_1}{v_1} = {A_2}{v_2} = {A_3}{v_3}\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1where A is the cross sectional area of the tube

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so we have the minimum value of the speed at section #3

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1next we have to consider the Theorem of Bernoulli: \[z + \frac{P}{\gamma } + \frac{{{v^2}}}{{2g}} = const\] where P is the pressure, and \gamma is the specific weight of the water

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so the pressure P is maximum at the section where the speed v is minimum. What can you conclude?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1more precisely, the quantity: \[\frac{P}{\gamma }\] is called the "groundwater level"

Ehsan18
 one year ago
Best ResponseYou've already chosen the best response.0We don't know anything about speed, probably depends upon the Area so its tube 3 most probably...what is your final answer?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! at the tube #3 the pressure is the highest and so it is the level reached by water

Ehsan18
 one year ago
Best ResponseYou've already chosen the best response.0Thanks guess I can close it now.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.