How many liters of 10% salt solution must be added to 20% salt solution in order to obtain 10 liters of 12% salt solution?

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How many liters of 10% salt solution must be added to 20% salt solution in order to obtain 10 liters of 12% salt solution?

Mathematics
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Say we need to add \(x\) liters of 10% salt solution, then the amount of 20% salt solution would be \(10-x\) as we want 10 liters
salt in \(x\) liters of 10% solution = \(0.1x\) salt in \(10-x\) liters of 20% solution = \(0.2(10-x)\)
Since we want the final solution to have 12% salt, add the previous expressions and set it equal to \(0.12(10)\) : \[0.1x +0.2(10-x) ~=~0.12(10) \] solve \(x\)

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Other answers:

oh it's 8 liters? am i right?
Correct!
Thank you :D
yw:)

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