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Please help with this. Thank you!

Mathematics
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\[x^2-4 \implies (x-2)(x+2)\]

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\[\frac{ 5 }{ x-2 } - \frac{ 20 }{ (x-2)(x+2) } = 1\] now you may use rule \[\frac{ a }{ b } - \frac{ c }{ d } = \frac{ ad-bc }{ bd }\]
yeah so there can be infinite solution but u cant try it out maybe is there a formula to find it out ?
It is not infinite solutions :P
how do u know it :/
An equation would have infinite many solutions if the equation has equal values for all variables. So if we had something such as y = x, unless stated otherwise.
buuuuuuuuuuuutt theres only one unknown right
Lets keep going, so we don't make mistakes, any idea kitty?
Well from what I'm doing, it's turn out to be answer B...:(
Well lets see...if we simplify it a bit more we should get \[5(x+2)-20=(x-2)(x+2) \implies 5x-10=x^2-4 \implies x^2-5x+6 = 0\] do you know how to factor?
I don't think you do, I think you're just guessing, if you factor \[x^2-5x+6=0\] you will get your answer.
there can be only one unknown? really? Last time I checked there are math problems that make you solve for 3 unknowns. x=? y = ? z = ? Factoring out that equation in this case, gives out more than one x = ?
I think they just assumed it before doing the math :P
*facepalm* which is a big no-no.

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