anonymous
  • anonymous
Please help with this. Thank you!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
anonymous
  • anonymous
@ganeshie8
Astrophysics
  • Astrophysics
\[x^2-4 \implies (x-2)(x+2)\]

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More answers

Astrophysics
  • Astrophysics
\[\frac{ 5 }{ x-2 } - \frac{ 20 }{ (x-2)(x+2) } = 1\] now you may use rule \[\frac{ a }{ b } - \frac{ c }{ d } = \frac{ ad-bc }{ bd }\]
anonymous
  • anonymous
yeah so there can be infinite solution but u cant try it out maybe is there a formula to find it out ?
Astrophysics
  • Astrophysics
It is not infinite solutions :P
anonymous
  • anonymous
how do u know it :/
Astrophysics
  • Astrophysics
An equation would have infinite many solutions if the equation has equal values for all variables. So if we had something such as y = x, unless stated otherwise.
anonymous
  • anonymous
buuuuuuuuuuuutt theres only one unknown right
Astrophysics
  • Astrophysics
Lets keep going, so we don't make mistakes, any idea kitty?
anonymous
  • anonymous
Well from what I'm doing, it's turn out to be answer B...:(
Astrophysics
  • Astrophysics
Well lets see...if we simplify it a bit more we should get \[5(x+2)-20=(x-2)(x+2) \implies 5x-10=x^2-4 \implies x^2-5x+6 = 0\] do you know how to factor?
Astrophysics
  • Astrophysics
I don't think you do, I think you're just guessing, if you factor \[x^2-5x+6=0\] you will get your answer.
UsukiDoll
  • UsukiDoll
there can be only one unknown? really? Last time I checked there are math problems that make you solve for 3 unknowns. x=? y = ? z = ? Factoring out that equation in this case, gives out more than one x = ?
Astrophysics
  • Astrophysics
I think they just assumed it before doing the math :P
UsukiDoll
  • UsukiDoll
*facepalm* which is a big no-no.

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