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anonymous

  • one year ago

Please help with this. Thank you!

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    @ganeshie8

  3. Astrophysics
    • one year ago
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    \[x^2-4 \implies (x-2)(x+2)\]

  4. Astrophysics
    • one year ago
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    \[\frac{ 5 }{ x-2 } - \frac{ 20 }{ (x-2)(x+2) } = 1\] now you may use rule \[\frac{ a }{ b } - \frac{ c }{ d } = \frac{ ad-bc }{ bd }\]

  5. anonymous
    • one year ago
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    yeah so there can be infinite solution but u cant try it out maybe is there a formula to find it out ?

  6. Astrophysics
    • one year ago
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    It is not infinite solutions :P

  7. anonymous
    • one year ago
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    how do u know it :/

  8. Astrophysics
    • one year ago
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    An equation would have infinite many solutions if the equation has equal values for all variables. So if we had something such as y = x, unless stated otherwise.

  9. anonymous
    • one year ago
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    buuuuuuuuuuuutt theres only one unknown right

  10. Astrophysics
    • one year ago
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    Lets keep going, so we don't make mistakes, any idea kitty?

  11. anonymous
    • one year ago
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    Well from what I'm doing, it's turn out to be answer B...:(

  12. Astrophysics
    • one year ago
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    Well lets see...if we simplify it a bit more we should get \[5(x+2)-20=(x-2)(x+2) \implies 5x-10=x^2-4 \implies x^2-5x+6 = 0\] do you know how to factor?

  13. Astrophysics
    • one year ago
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    I don't think you do, I think you're just guessing, if you factor \[x^2-5x+6=0\] you will get your answer.

  14. UsukiDoll
    • one year ago
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    there can be only one unknown? really? Last time I checked there are math problems that make you solve for 3 unknowns. x=? y = ? z = ? Factoring out that equation in this case, gives out more than one x = ?

  15. Astrophysics
    • one year ago
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    I think they just assumed it before doing the math :P

  16. UsukiDoll
    • one year ago
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    *facepalm* which is a big no-no.

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