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DominantVampire
 one year ago
kindly help please.
A Block Of Mass 12 kg
DominantVampire
 one year ago
kindly help please. A Block Of Mass 12 kg

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DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0a block of mass 12 kg is released from rest om a frictionless incline of the angle theta=30 below the block is a spring having spring constant 10^4 N/m. the block stops momentarily when it compresses the spring by 4 cm. how far does the block move down the incline from its rest position to this stopping point

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0dw:1434185406478:dw

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0no body knows perhaps, sighs.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know how to use energy conservation??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yep... initial energy will be the potential energy of the block and the final energy will be the spring extension.. can you relate?

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0the Ki is 0 and Uf would be zero as well i guess

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Uf would not be zero as the spring is compressed and is having potential energy its like the GPE is getting converted to spring energy

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0GPE is gravitational potential energy

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0the spring constant is 10,000N/m ?

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0will it be mgh=1/2 kx^2

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0and plug in the values? h is not given

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0h is what you have to find!!

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0v have to find out h?

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0so it becomes like h = [(1/2)kx^2][mg]

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0h = [(1/2)kx^2] / [mg]

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0the h is 6.80 m

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0sin(30) = h/x to determine the hypotenuse

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0now h/sin30=x ?????

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0the ans is 13.6 ????
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