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DominantVampire
 one year ago
a block of mass 12 kg is released from rest om a frictionless incline of the angle theta=30
below the block is a spring having spring constant 10^4 N/m. the block stops momentarily when it compresses the spring by 4 cm. how far does the block move down the incline from its rest position to this stopping point
DominantVampire
 one year ago
a block of mass 12 kg is released from rest om a frictionless incline of the angle theta=30 below the block is a spring having spring constant 10^4 N/m. the block stops momentarily when it compresses the spring by 4 cm. how far does the block move down the incline from its rest position to this stopping point

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1Gravitational potential converts to spring potential as block slides and spring compresses. So balance the 2 taking account of slope.

shamim
 one year ago
Best ResponseYou've already chosen the best response.1Potential energy of compressed spiring=.5kx^2=.5*10^4*.04^2=?

shamim
 one year ago
Best ResponseYou've already chosen the best response.1Potential energy at the top of inclined plane=kinetic energy at the bottom of inclined plane=mgh=12*9.8*h

shamim
 one year ago
Best ResponseYou've already chosen the best response.1Potential energy of spring=kinetic energy of block

shamim
 one year ago
Best ResponseYou've already chosen the best response.1At last u hv to find out the length of inclined plane

Pawanyadav
 one year ago
Best ResponseYou've already chosen the best response.0MgHsin30 ⏰=0.5×10^4×4^2

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0@sikinder is this formula above written right which as been suggested

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0but the ans is totally diff. the h i get is 0.136m

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i was thinking that ur calculation method is right @DominantVampire

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes i think @DominantVampire

DominantVampire
 one year ago
Best ResponseYou've already chosen the best response.0alright. thankyou.
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