help_people
  • help_people
The table below shows data for a class's mid-term and final exams: Mid-Term Final 100 98 100 95 100 93 95 91 95 88 92 82 92 78 88 78 85 65 75 60 Which data set has the largest IQR? Mid-term exams Final exams They have the same IQR There is not enough information
Mathematics
chestercat
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help_people
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Loser66
  • Loser66
What is IQR?
help_people
  • help_people
interquartile range

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help_people
  • help_people
phi
  • phi
you should find the median of each data set divide the data set into two halves: one below and one above the median then find the median of each half IQR= top median - bottom median
Loser66
  • Loser66
What is the median of the mid-term set?
phi
  • phi
because the numbers are sorted, and you have 10 numbers total, look at the middle number of the first 5 (i.e the 3rd number on the list) and the middle number of the lower 5 (i.e. the 3rd from the bottom) subtract those two numbers
help_people
  • help_people
there are two medians 95 and 92
help_people
  • help_people
for the mid-term
phi
  • phi
look at the middle number of the first 5 (i.e the 3rd number on the list)
phi
  • phi
in other words, if you look only at 100 100 100 95 95 (the first 5 numbers of the mid-term) the median of those is the middle number and is 100
phi
  • phi
now do the same thing for the bottom 5 numbers 92 92 88 85 75
help_people
  • help_people
median of those is 88
phi
  • phi
you should get 88 for the median of the bottom 5 numbers. now you can find the IQR 100 - 88
help_people
  • help_people
12
phi
  • phi
now do the same thing for the other data set
phi
  • phi
find the 3rd number on the top 5 find the 3rd number of the bottom 5 subtract
help_people
  • help_people
93 and 78? @phi
phi
  • phi
yes, now find the iqr by subtracting big - little
help_people
  • help_people
um ok 15
phi
  • phi
finally, which data set has the bigger iqr?
help_people
  • help_people
final
phi
  • phi
yes
help_people
  • help_people
ty may you help w. two more?
phi
  • phi
if you make a new post, please
help_people
  • help_people
ok

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