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anonymous
 one year ago
let
A=M2(Z)
be the ring of
2×2
integral matrices the identity of A,
IA
anonymous
 one year ago
let A=M2(Z) be the ring of 2×2 integral matrices the identity of A, IA

This Question is Closed

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4is the question asking for the identity matrix?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0HMM. dw:1434206105315:dw

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4\[\begin{array}{cc} 1 & 0 \\ 0 & 1 \end{array}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let G be a group and H1 , H2 normal subgroups of .one of these is a normal subgroup of G

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4whew i thought it was going to be some hard ring question, not a nice easy one

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4you lost me there, was it perhaps a copy and paste fail?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01)H1 INTERCEPT H2 2)H1 UNION H2 3)H1H2 4)AXB

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4if \(A_1,H_2\) are normal in \(G\) then \(H_1\cap H_2\) is as well, it is a straightforward check

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4depending of course on what your definition of a normal subgroup is there are a couple

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0OK MA. HAVE SOME MORE...

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4wait, you don't have to prove it, just pick one?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If R and R'are rings, a mapping ϕ:R→R′ ring ho morphism if any of these happen ∀a,b,∈R

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ϕ(a+b)=ϕ(a)+ϕ(b) ϕ(a/b)=ϕ(a)−ϕ(b) ϕ(a.b)=ϕ(a)ϕ(b) A and C only

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4wow an abstract algebra class with multiple guess questions? no proofs just pick?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0IM VERY CONFUSE and the book i have does note contain all these.

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4guess, i bet you get it on the first try or google ring homorphisms one hint, no one says division is even DEFINED in a ring

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. i thought as much. it is multiplication and addition . right?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4or just read the top line here https://en.wikipedia.org/wiki/Ring_homomorphism

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0An isomorphism of a ring is both an epimorphism and ________________ Monomorphism Endomorphism Automorphism homomorphism

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think it is homomorphism

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4i am not sure what "homomorphism" of a ring means, a homo from on ring to another?

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4isomorphism means a homomorphism that is both injective and surjective, or in this language "epi" and "mono"

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4if it is a epimorphism, it is already a homomorphism, don't pick that one

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4ok actually i was not being precise epi is not exactly surjective and mono is not exactly injective, but you can think of them that way

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok. which means Monomorphism is the answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks... A endomorphism of a ring R is a _________ of R into itself

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Monomorphism Endomorphism Automorphism homomorphism

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0does are the options

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4scratch that. go with homo

misty1212
 one year ago
Best ResponseYou've already chosen the best response.4i gotta run, good luck

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Let R and S be rings and ϕ:R→S be an isomorphism, the ϕ is __________________

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0monomorphism endomorphism Automorphism homomorphism

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hello @ikram002p please help

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.0it should be homomorphism its the condition of being isomorphic

ikram002p
 one year ago
Best ResponseYou've already chosen the best response.0why dont u start a new question so i would be able to help ?
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