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anonymous
 one year ago
Trig / Pre Cal/identities Am I on the right path?
Please do not give the answer. Here is the problem
\( \frac{(\sin x \cos x)*2}{cos} = \sec x  \cos x\)
I am working on the left side and need to prove it equals the right. This is what I have done so far
\( \frac{(\sin^2 x  2(\cos x)(\sin x)+\cos^2 x}{\cos x} = \sec x  \cos x\)
Am I going about this the right way because I don't see where to go from here. Thank you.
anonymous
 one year ago
Trig / Pre Cal/identities Am I on the right path? Please do not give the answer. Here is the problem \( \frac{(\sin x \cos x)*2}{cos} = \sec x  \cos x\) I am working on the left side and need to prove it equals the right. This is what I have done so far \( \frac{(\sin^2 x  2(\cos x)(\sin x)+\cos^2 x}{\cos x} = \sec x  \cos x\) Am I going about this the right way because I don't see where to go from here. Thank you.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is suppose to be Trig / Pre Cal/identities Am I on the right path? Please do not give the answer. Here is the problem \( \frac{(\sin x \cos x)^2}{cos} = \sec x  \cos x\) I am working on the left side and need to prove it equals the right. This is what I have done so far \( \frac{(\sin^2 x  2(\cos x)(\sin x)+\cos^2 x}{\cos x} = \sec x  \cos x\) Am I going about this the right way because I don't see where to go from here. Thank you.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is where I am at. Am I on the right path and where do I go from here because I do not see anything. \( \frac{\sin^2 x  2(\cos x)(\sin x)+\cos^2 x}{\cos x} = \sec x  \cos x\)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0hmm well....... i guess both sides are not equal

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0\(\color{blue}{\text{Originally Posted by}}\) @Nixy Made a mistake \(\color{blue}{\text{End of Quote}}\) what ?? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is suppose to be \( \frac{(\sin x \cos x)^2}{cos} = \sec x  2\sin x \) And I am at \( \frac{\sin^2 x  2(\cos x)(\sin x)+\cos^2 x}{\cos x} = \sec x  2\sin x \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was typing it in too fast and made a boo boo. Sorry about that.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Try sin² x = 1  cos² x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So the numerator becomes \[1  cos^2 x  2 (sin x)(cos x) + cos^2 x\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0that's right or just put 1 sin^2x+cos^2 =1 you will get the same answer :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I did that a min ago and it did not work but re looked at it and I see where I made my mistake. Thank you all

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think I over think these things at time. One minute I am rolling through them and then I get snagged by the simplest thing lol Thank you all
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