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anonymous
 one year ago
What power of an engine is required to pump 2450 N of water per second from a well 50 m deep to the surface?
(a) 2.45*10^3 watts
(b) 2.45*10^4 watts
(c) 2.45*10^5 watts
(d) none of these
anonymous
 one year ago
What power of an engine is required to pump 2450 N of water per second from a well 50 m deep to the surface? (a) 2.45*10^3 watts (b) 2.45*10^4 watts (c) 2.45*10^5 watts (d) none of these

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino please can you solve it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so work is Fd so the answer is 2450 N times 50 m

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ignore my last answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think you're right because a watt is a Nm/s, so the units work out

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1we have to consider the manometric head H, which is about 50 m, so the requested power P is: \[\Large P = F\left( {H + h} \right) = 2450\left( {50 + 50} \right) = ...?\] being h the deepness of the well

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1sorry H is equal to the ratio between the pressure difference and the specific weight of the water and H+h is the manometric head or manometric prevalence

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would you please tell me a little about manometric head,50 m deepness is okay to understand but what about additional 50m that you added

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1since the formula for computing the power, is: \[\large P = \frac{{FH}}{t}\] where H is the total prevalence, whose formula is: \[H = h + \frac{{\Delta p}}{\gamma }\] \Delta p is the difference between the pressures

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434218860993:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434218975568:dw

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1so: \[\frac{{\Delta p}}{\gamma } = 5 \times 10.33 = 51.65\;meters\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1please keep in mind that 10.33 meters is the maximum aspiration height for a pump

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1and: 1 athmosphere is equivalent to 10.33 meters of water

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so you think that 2.45*10^5 would be the correct option?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are you confirmed liano?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0. i'd go with d) but i'd like the OP to post the answer when that becomes apparent

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.1yes! I confirm my answer above!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i asked this to my friend he say to me that you can apply formula \[P=mgh/t\] since W=mgh \[P=W/t\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so after this answer is none of these,the (d) option

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am so much confused about the answer,but i think what you are telling is also correct!
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