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anonymous
 one year ago
HELP PLEASE!
The function below shows the number of car owners f(t), in thousands, in a city in different years t:
f(t) = 0.25t2  0.5t + 3.5
The average rate of change of f(t) from t = 2 to t = 6 is_________ thousand owners per year. (3 points)
anonymous
 one year ago
HELP PLEASE! The function below shows the number of car owners f(t), in thousands, in a city in different years t: f(t) = 0.25t2  0.5t + 3.5 The average rate of change of f(t) from t = 2 to t = 6 is_________ thousand owners per year. (3 points)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Michele_Laino @nincompoop

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0the average rate R, is given by the subsequent formula: \[R = \frac{{f\left( 6 \right)  f\left( 2 \right)}}{{6  2}}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so it would be R= f(4) over 4?? @Michele_Laino

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Rate of change is the change in y over the change in x. So plug in t = 2 into the equation to find f(2) and t = 6 into the equation to find f(6). Then do [ f(x)  f(2) ] / (62)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then would the answer be 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cause it would be f(4) over 4?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0f(2) = 3.5 f(6) = 9.5 9.5  3.5 = 6 6 2 = 4 Rate of change is 6/4 = 3/2

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.0no, you have to compute this quantity: \[\begin{gathered} R = \frac{{f\left( 6 \right)  f\left( 2 \right)}}{{6  2}} = \hfill \\ \hfill \\ = \frac{{\left( {0.25 \times 36  0.5 \times 6 + 3.5} \right)  \left( {0.25 \times 4  0.5 \times 2 + 3.5} \right)}}{4} = ...? \hfill \\ \end{gathered} \]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 1.5 would be the rate of change

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok thank you soo much! :)
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