Find the value of the variable if P is between J & K JP= 3y + 1 PK= 12y - 4 JK = 75

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Find the value of the variable if P is between J & K JP= 3y + 1 PK= 12y - 4 JK = 75

Geometry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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you need to draw it out JP=3Y +1 PK=12y-4 JK=75
on a number line
if it is two dimensional

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i am assuming it is on a number line
JP + PK = JK = 75 3y + 1 + 12y - 4 = 75 15y - 3 = 75 15y = 78 y = 5.2 Plug in y = 5.2, assume that the number line starts at 0 and ends at 75 |dw:1434212648936:dw| Since the distance from J to P is going to be the coordinate point of P, P = 16.6 Someone tell me if I did this wrong....

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