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Can you help me solve it?

Sure. :)

\(\Huge a^2+b^2=c^2\)

So, 6^2+11.7^2=C^2?

a and b are the two sides and c is the hypotenuse.

a and b are the two sides that make a right angle.

AO would be the hypotenuse.

Ohh. So, the answer would be 6^2+11.7^2?

\(\Huge 6^2+b^2=11.7^2\)

\[6^2+11^2\]

oops, I messed up.

I just substituted the values to where they belong.

Oh, so it would be C?

Can you tell me how you got C as the answer?

Yes, so I put in what 11.7^2 was and got 136.89. Then I put in 6^2+10.0^2 and got 136.

Correct but you did it the wrong way. The correct way it to do \(11^2-6^2=x^2\).

Can you help me with another question?(:

|dw:1434216486710:dw|
this straight line add up to 180 degree

set an equation |dw:1434216532709:dw|
\[\huge\rm 50+90+x=180\] solve for x

impossible !
i told you
straight line add up to 180 degree all 3 angles should add up to 180 degree

So, 38?

typo it's 92
\[\huge\rm 50+92+x=180\] solve for x

yep

So, it's 38. And can you help me with another question?

i'll try

Can someone help?

close this post and make a new one so other people can help i hve to go