A sandbag was thrown downward from a building. The function f(t) = -16t2 - 32t + 128 shows the height f(t), in feet, of the sandbag after t seconds.
Part A: Factor the function f(t) and use the factors to interpret the meaning of the x-intercept of the function. (4 points)
Part B: Complete the square of the expression for f(x) to determine the vertex of the graph of f(x). Would this be a maximum or minimum on the graph? (4 points)
Part C: Use your answer in part B to determine the axis of symmetry for f(x)? (2 points)

- anonymous

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- katieb

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- anonymous

giving medals for answers!!!!!!!!!!

- welshfella

First take. -16 out
-16(t^2+2t-8)
Can you factor this?

- anonymous

I have no clue how to do any of this...

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## More answers

- welshfella

This factors to the from
-16(t+a)(t+b)
And to get the x intercepts equate to zero and sovereign for t
One of these values of t will be the times when height is zero

- welshfella

* solve for t

- nincompoop

well let us understand what the equation meant first

- nincompoop

solving for t, or anything is pretty useless if you do not understand what it is

- anonymous

wait so I substitute the 0 for t?

- anonymous

@welshfella ??????????

- nincompoop

The function \(f(x) = ax^2 + bx + c \) gives you a general clue about the location or position of the object that is you are working on. The c in the function tells you how high or how far you are starting from.
|dw:1434219502610:dw|

- nincompoop

You are being asked to factor the function \(f(x) = -16t^2 - 32t + 128 \) and was asked to interpret the x-intercepts.
But before you jump into factoring it, you need to remember the general graph for a quadratic equation. It is called a quadratic equation because the highest exponent is 2.
|dw:1434219835751:dw|

- nincompoop

The x-intercept in a quadratic equation is the location where the graph intercepts the x-axis. If you look closely, the value of y in the x-axis is zero.

- nincompoop

The x-intercept in a quadratic equation is the location where the graph intercepts the x-axis. If you look closely, the value of y in the x-axis is zero. And if we interpret this into falling object from a particular height or object thrown from the ground, the intercepts are the zeroes - one of them is where you started.
if you make t equals to zero \(f(t) = -16t^2 - 32t + 128 \) you will get what I told you in the beginning - the position function, that is where your object is.
|dw:1434220223115:dw|

- MeowLover17

AGAINST CODE OF CONDUCT!!!!!

- anonymous

This is a Q on a test.

- MeowLover17

Yep ^

- anonymous

We help you study FOR testsâ€¦ not ON the test.

- nincompoop

do you have a proof that this is from an exam that he/she is taking now?

- MeowLover17

I have proof

- anonymous

So do I.

- nincompoop

then report the person to the school.

- MeowLover17

ITS AN online course

- MeowLover17

Known as florida virtual school

- anonymous

We don't know the identity of this personâ€¦ so we can't report it.

- MeowLover17

I understand that you dont understand the question but you can't be asking that on here. Since its a test question

- MeowLover17

Or Quiz question

- nincompoop

well I have not given any answer. everything has just been a general description, and I just used the height as an example.

- MeowLover17

@nincompoop Keep helping him/her

- MeowLover17

Just dont give a direct answer

- nincompoop

I will be back later. you can argue with the person while I eat

- anonymous

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- anonymous

http://prntscr.com/7gk9u7

- anonymous

If you see the date (5/1/15) I'm not making this up.

- anonymous

You just mentioned test towards the end.

- anonymous

"(4 points)"
ok.

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