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Liv1234
 one year ago
SOMEONE PLEASE HELP ME WITH A FEW QUESTIONS
Liv1234
 one year ago
SOMEONE PLEASE HELP ME WITH A FEW QUESTIONS

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kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1The tangentsecant theorem: \(CD^2 = CB \times CA\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0@kc_kennylau Can you help me through the problem?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Or anyone that can help please.

Godlovesme
 one year ago
Best ResponseYou've already chosen the best response.0let's use the formula @kc_kennylau provided :3 \[CD^2 = BC+ AC\]

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1@Godlovesme that was times

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Thank you for helping by the way.

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0So, how would I use the formula to find out the answer?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0@Godlovesme @kc_kennylau

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, you have the length of \(CD\) and \(CB\)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, the formula is \(CD^2 = CB\times CA\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with another question(:

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1A is actually the length of \(CA\)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1You're asked to find the length of \(BA\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Yes, it is because 30^2=900 and 17*52.9=900, right?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Ohh I see what you're saying sorry my bad.

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0So, where did I mess up though?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, you only found the length of \(CA\).

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1How do you find the length of \(BA\) from that?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, we can see that \(CA  CB = BA\)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Remember that \(CA = 52.9\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0It's 35.9! Because 52.917=35.9

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me again??

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, can you tell me \(m\angle OAB\)?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0No, I don't understand it. :/ (and by the way I need help with like 3 other questions after this one if that's okay)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1I mean the angle \(OAB\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0I don't know how to find it out that's what I'm confused about.

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, since \(AB\) is tangent, the angle is actually \(90^\circ\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Okay, so what do we do from there?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1So, we can actually apply the Pythagoras' Theorem

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Ohh okay. So, what was the formula for that?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1\(OA^2+AB^2=OB^2\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Did I put the numbers in wrong?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Can we find \(OC\)?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0I think we can, but I'm not sure how.

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, it is another radius

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1All radius have the same length

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0So, what would it be then?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1\(OA\) is another radius

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Em... what are we talking about?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, the radius is 24

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay, so OC would be 24?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1So how long is \(OB\)?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1em.. i'm talking about \(OB\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0I'm not sure what it would be, is there a way to find out?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, OB is just OC + CB

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Nope. CB is actually 27

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0So, would the answer to the question be 51?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Nope, we need to find \(AB\)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1the pythagoras' theorem! :D

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Ohh. And what was the formula again aha?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1\(OA^2+AB^2=OB^2\)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0So, 27^2+AB^2=51^2. 51^2=2601. Right?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0I might have messed up with that a little.

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1it should be 24^2 instead of 27^2

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Ohh okay. 24^2+AB^2=51^2.

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0It would be 45. Which is A. Can you help me again?(:

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Well, it's difficult to discuss without names

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Without names of vertices

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1I can't refer any line

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Want me to post another question instead?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434224619983:dw

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay, that's gonna make it a lot easier.

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1So, O is the centre of the circle

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1And OM makes a right angle with AB

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1(Just remember this result :p)

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0So, what do we start out with?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1I mean that M divides AB in half

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1yes, that would be MB

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0And half of 21 is 10.5

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1dw:1434225065530:dw

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Then what would we do?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Apply the Pythagoras' Theorem

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Can you write it out for me again please?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1\(OM^2+MB^2=OB^2\)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1No, OB^2 is 135.25

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0I know, but when you do 135.25^2 you get 18300(rounded)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1No, OB^2 is 135.25, so you root it, not square it

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Can you help me with it?

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1The angle at center \(m\angle O\) is twice the angle at circumference \(m\angle R\) yes

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0And this is the last one.

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Secant secant theorem: \(CA\times CB = CE \times CD\)

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, how to find CA? It's the sum of two lines again

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1You're asked to find DE

kc_kennylau
 one year ago
Best ResponseYou've already chosen the best response.1You need to deduct 4

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0Ohh, that makes sense, so C?

Liv1234
 one year ago
Best ResponseYou've already chosen the best response.0YAY thank you so much for helping(:
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