anonymous
  • anonymous
A rectangular barge 7 m long and 2 m wide floats in fresh water. How much will the barge sink when loaded with 600 kg of sand? Show all calculations leading to an answer.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@sleepyjess @Michele_Laino
Michele_Laino
  • Michele_Laino
here we have to apply the Principle of Archimede
anonymous
  • anonymous
I think the answer is 40mm"

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More answers

anonymous
  • anonymous
Water Density = 1,000kg/m^3 600/1,000= .6m^3 Area = 15m^2 V= (L)(W)(D)= .6^3 D= .6m^3/15m^2 = .04m = 40mm"
Michele_Laino
  • Michele_Laino
If I call with "h" the sinking level, then we can write: \[\Large LWh\delta g= Mg\] where: L is the length of the barge, W is the width of the barge \delta is the density of water g is gravity M is the mass of the loaded sand
Michele_Laino
  • Michele_Laino
is 600 Kg the mass of the sand ot its weight?
Michele_Laino
  • Michele_Laino
or*
Michele_Laino
  • Michele_Laino
I think that M=600 Kg is the mass of the sand
anonymous
  • anonymous
yeah i think mass
Michele_Laino
  • Michele_Laino
so we get: \[\Large h = \frac{M}{{LW\delta }} = \frac{{600}}{{7 \times 2 \times 1000}} = ...\]
Michele_Laino
  • Michele_Laino
what is h?
anonymous
  • anonymous
the depth of sinking?
Michele_Laino
  • Michele_Laino
yes!
anonymous
  • anonymous
In mine i hade it D
anonymous
  • anonymous
Made*
Michele_Laino
  • Michele_Laino
I got: \[\Large h \cong 43\;mm\]
Michele_Laino
  • Michele_Laino
so, you are right!
anonymous
  • anonymous
Yay!
Michele_Laino
  • Michele_Laino
:)
anonymous
  • anonymous
When a steadily-flowing gas flows from a larger-diameter pipe to a smaller-diameter pipe, what causes the pressure in the smaller pipe to drop? Use 3 – 4 complete sentences to explain your answer.
anonymous
  • anonymous
do you know this? lol
Michele_Laino
  • Michele_Laino
if we can neglect all loss of energy of the gas, then we can apply the Principle of Bernoulli furtermore we can apply the equation of continuity
anonymous
  • anonymous
@kaitlynmcurtis Bernoulli's principle states that the same V/s of fluid flowing will remain the same. If the radius of a pipe drops, then then the fluid has to travel faster through the pipe in order to maintain the same Volume per second... the only way the fluid can move faster is if there is a pressure drop from the larger pipe into the smaller pipe. Hope the helps!
Michele_Laino
  • Michele_Laino
for example, the equation of continuity is: \[\Large {A_1}{v_1} = {A_2}{v_2}\] |dw:1434221385263:dw| A is the cross sectional area v is the speed of the gas
Michele_Laino
  • Michele_Laino
so when the cross sectional area is minimum, then the speed of the gas is maximum
Michele_Laino
  • Michele_Laino
I have assumed that the density of our gas doesn't change as we go from section #1 to section #2
Michele_Laino
  • Michele_Laino
next the Principle of Bernoulli is: \[\Large gz + \frac{P}{\delta } + \frac{{{v^2}}}{2} = const\] where g is gravity, and z is the geodesic height
anonymous
  • anonymous
I think I got this one done, could you guys help me with another? @cramos725 @Michele_Laino
Michele_Laino
  • Michele_Laino
|dw:1434221789810:dw|
Michele_Laino
  • Michele_Laino
ok!

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